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RSB [31]
3 years ago
12

A die is thrown . find the probability of (1) a multiple of 2 or 3​

Mathematics
1 answer:
tangare [24]3 years ago
7 0

Answer:

A die is thrown which means that it can land on either 1-6 on the die.So if you want to find the probability of the multiple of 2 or 3....we have multiplies of 2 in the die from 1-6 which is 2,4 and 6 if you count them they are just 3 numbers and since there is a probability of it to land on any of them it will be 3/6 which is 1/2 if yiu divide by 3 to it's lowest term....Then multiple of 3 is 3,and 6.which will be 2/6 which is 1/3 if u cut to its lowest term. Or in the question means addition sign in probability then it is 2 or 3 which is (1/2)+(1/3)=5/6.Thank you for the question

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Answer:

I answered your last question also

2 log3x – 2 logx3 -3 <0

\mathrm{Subtract\:}2\log ^3\left(x\right)\mathrm{\:from\:both\:sides}

2\log ^3\left(x\right)-2logx^3-3-2\log ^3\left(x\right)

\mathrm{Simplify}

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\mathrm{Add\:}3\mathrm{\:to\:both\:sides}

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\mathrm{Simplify}

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Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)

\left(-2logx^3\right)\left(-1\right)>-2\log ^3\left(x\right)\left(-1\right)+3\left(-1\right)

\mathrm{Simplify}

2lx^3og>2\log ^3\left(x\right)-3

\mathrm{Divide\:both\:sides\:by\:}2lx^3o;\quad \:l>0

\frac{2lx^3og}{2lx^3o}>\frac{2\log ^3\left(x\right)}{2lx^3o}-\frac{3}{2lx^3o};\quad \:l>0\\

\mathrm{Simplify}

g>\frac{2\log ^3\left(x\right)-3}{2lx^3o};\quad \:l>0

Step-by-step explanation:

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