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Oksanka [162]
3 years ago
13

A rectangles length and width are in a ratio of 17:2. The area is 136 square yards. What are the length and width.

Mathematics
1 answer:
Semmy [17]3 years ago
6 0
I hope this helps you

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CAN SOMEONE HELP ME WITH PATTERN 1
jeyben [28]
1- 6
2- 4
3- 2
And that’s all I can tell you? It’s decreasing so I don’t think 10 would have any stars unless if negative numbers are allowed
5 0
3 years ago
What is the definition of the union of two mathematical sats ,A and B
Zepler [3.9K]

Set contain all the elements present in both the sets.

<u>Step-by-step explanation:</u>

Definition:

The union of two mathematical sets can be defined as the set that consists of all the elements present in both the sets without the repetition of elements.

Consider, A  and B be the sets.

A =  {1,7,5,6,0}

B = {2,3,4,5,6}

U is the symbol of union of sets, so A U B = {1,2,3,4,5,6,7,0}

Here 5 and 6 are the elements present in both the sets, so written only once in the set of A U B.

5 0
3 years ago
Three of the angles of a polygon are
zmey [24]

Answer:

three angles of a polygon are each 105.5,the sum of the angles in the polygon is 2520. find each of the other angles if they are equal to each other. For a polygon with n sides and n angles, the sum of the measures of all the interior angles equals (n-2)180 degrees. 16-3=13

6 0
3 years ago
Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.
lesya [120]

Answer:

0.1994 is the required probability.      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling =

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{5.3}{\sqrt{20}} = 1.1851

P(sample of 20 boxers is more than 167 pounds)

P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)

= 1 - P(z \leq 0.8438)

Calculation the value from standard normal z table, we have,  

P(x > 167) = 1 - 0.8006= 0.1994 = 19.94\%

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

3 0
3 years ago
At a local print shop, 18 copies can be made for $6. At this rate, how much would it
Ber [7]

Answer: to make 78 copies it cost 26 dollars.

Step-by-step explanation:

18 copies - 6 dollars

78 copies - x dollars

Hence,

\displaystyle\\x=\frac{78*6}{18} \\\\x=\frac{26*3*6}{3*6} \\\\x=26 \ dollars

5 0
2 years ago
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