Answer:
It is not normally distributed as it has it main concentration in only one side.
Step-by-step explanation:
So, we are given that the class width is equal to 0.2. Thus we will have that the first class is 0.00 - 0.20, second class is 0.20 - 0.40 and so on(that is 0.2 difference).
So, let us begin the groupings into their different classes, shall we?
Data given:
0.31 0.31 0 0 0 0.19 0.19 0 0.150.15 0 0.01 0.01 0.19 0.19 0.53 0.53 0 0.
(1). 0.00 - 0.20: there are 15 values that falls into this category. That is 0 0 0 0.19 0.19 0 0.15 0.15 0 0.01 0.01 0.19 0.19 0 0.
(2). 0.20 - 0.40: there are 2 values that falls into this category. That is 0.31 0.31
(3). 0.4 - 0.6 : there are 2 values that falls into this category.
(4). 0.6 - 0.8: there 0 values that falls into this category. That is 0.53 0.53.
Class interval frequency.
0.00 - 0.20. 15.
0.20 - 0.40. 2.
0.4 - 0.6. 2.
Answer:
I think its rational
Step-by-step explanation:
Answer:
B,
Step-by-step explanation:
The height of a rectangle is 12 units. The rectangle has an area greater than 25 square units. What are the possible values for the base of the
rectangle, n?
Answer:
Redskins cost $0.25 and golden roughs cost $0.35.
Step-by-step explanation:
Let r be the cost of a redskin and g the cost of golden roughs. So we have the system of equations:
r + 4g = 1.65
2r + 3g = 1.55
Multiply the first equation by -2:
-2r - 8g = -3.30
Adding this to the second equation:
-5g = -1.75
g = 0.35.
Now substitute this into the first equation:
r + 4*0.35 = 1.65
r = 1.65 - 1.40
r = 0.25.
Answer:
9.1 is the nearest tenth
9.11 to the nearest hundredth
just slightly to the right of 9.1
Step-by-step explanation:
sqrt(83)
sqrt(81) = 9
So we know that it is slightly greater than 9
9.1*9.1 =81.81
9.2*9.2=84.64
9.1 is closer
9.11 * 9.11 =82.9921
9.12 * 9.12 =83.1744
9.11 is closer