Answer:
Step-by-step explanation:
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Answer:
A) f^-1(x)=(x-8)^3+2
Step-by-step explanation:
To find the function inverse, switch the x with y and solve for y.
![y=\sqrt[3]{x-2}+8 \\\\x=\sqrt[3]{y-2}+8\\\\(x-8)^3 = y-2\\\\ (x-8)^3 + 2 = y](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7Bx-2%7D%2B8%20%5C%5C%5C%5Cx%3D%5Csqrt%5B3%5D%7By-2%7D%2B8%5C%5C%5C%5C%28x-8%29%5E3%20%3D%20y-2%5C%5C%5C%5C%20%28x-8%29%5E3%20%2B%202%20%3D%20y)
To find Angle A we use cosine
cos ∅ = adjacent / hypotenuse
From the question
The adjacent is 17
The hypotenuse is 38
So we have
cos A = 17/38
A = cos-¹ 17/38
A = 63.4
<h3>A = 63° to the nearest degree</h3>
To find Angle C we use sine
sin ∅ = opposite / hypotenuse
From the question
The opposite is 17
The hypotenuse is 38
So we have
sin C = 17/38
C = sin-¹ 17/38
C = 26.57
<h3>C = 27° to the nearest degree</h3>
Hope this helps you
Answer:
How to factor out a polynomial with a 3rd degree-• well here is a For example, let G(x) = 7x³ – 125. Then factoring this third degree polynomial relieve on a differences of cubes as follows: (2x – 5) (4x² + 20x + 25), where ²x is the cube-root of 8x³ and 5 is the cube-root of 1256
