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vovikov84 [41]
3 years ago
10

What basic trigonometric identity would you use to verify that csc x sec x cot x = csc^(2)x

Mathematics
2 answers:
Scilla [17]3 years ago
7 0

Answer:

Step-by-step explanation:

Using the basic trigonometry identity, we have

cosecx=\frac{1}{sinx}, secx=\frac{1}{cosx} and cotx=\frac{cosx}{sinx}

Thus, the given equation is:

{\text}{cosecx secx cotx}=cosec^2x

Taking the LHS of the above equation , we get

={\text}{cosecx secx cotx}

=cosecx(\frac{1}{cosx})(\frac{cosx}{sinx})

=cosec^2x

=RHS

Hence proved.

Nostrana [21]3 years ago
4 0

Answer:

 cotx=\frac{cosx}{sinx}

 secx=\frac{1}{cosx}

cscx=\frac{1}{sinx}


Step-by-step explanation:

1. Keeping on mind that secx=\frac{1}{cosx} and  cotx=\frac{cos}{sin}, you can rewrite it as following:

cscx(\frac{1}{cosx})(\frac{cosx}{sinx})

2. Then, when you simplify it, you obtain:

cscx\frac{1}{sinx}

3. So, keeping on mind that cscx=\frac{1}{sinx}, you have:

cscx*cscx=csc^{2}x



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