Given
piece of plywood measuring 2 feet 8 inches long by 2 feet 4 inches wide.
What is the area of a piece of plywood .
To proof
Here plywood shape in the form of rectangle.
Formula
Area of rectangle = Length×Breadth
As given in the question
Length =2 feet 8 inches
Breadth = 2 feet 4 inches
First convert feet into inches
1 feet = 12 inches
2 feet 8 inches = 2×12 + 8
= 32 inches
Also
2 feet 4 inches = 2×12 +4
= 28 inches
put is in the above formula
Area of plywood = 32 ×28
= 896 inches²
Therefore option (b) is correct
Hence proved
Answer:
Length: 15m
Width: 17m
Step-by-step explanation:
Add 3 to each number (12 +3=15, 14+3=17)then multiply them an you’ll get 255 square meters
Hope its helpful
Answer:the independent variable is x, the number of hours of work.
The dependent variable is y, the total charge for x hours of work.
Step-by-step explanation:
A change in the value of the independent variable causes a corresponding change in the value of in dependent variable. Thus, the dependent variable is is output while the independent variable is the input
For each visit, he charges $25 plus $20 per hour of work. The linear expression that represents the total amount of money that Ethan earns per visit is y = 25 + 20x.
Since the total amount charged, y depends on the number of hours of work, x, it means that the dependent variable is y and the independent variable is x
Answer:
Step-by-step explanation:


case~2

Answer:
c find the value
Step-by-step explanation:
plz workout