To find the gradient of a line we first hv to find the formula
so Gradient=√X1-x2and √y1-y2
((-2,1) and (0,-5)) line 1
line 2(0,-1) and (1,0)
first we will work for line 1
X1 is -2
X2 is -0
Y1 is 1
Y2 is -1
so y=x-1
so we substitute the values
1--1=-2--0
so,
1+1=-2+0
2=-2
-0
So the equation 1 line 1 is not true
we will now go to equation 2 line 2
the equation is 3x+y=-5
we substitute the values
3(-2--0)+1--1=-5
3(-2)+-2=-5
-6+-2=-5
-8= -5
group like terms
Ur answer should look like this -3
So the answer is 3x+y=-5
-11-8-13(-10)
First, multiply since multiplication goes before subtraction according to the order of operations.
-11-8+130
Then add and subtract from left to right.
-11-8= -19
-19+130=111
Final answer: 111
Answer:
No its not
Step-by-step explanation:
When 42(x + 14y) is simplified:
42(x + 14y)
Expand and remove the brackets. Remember brackets mean to multiply.
42*x
42x
42*14y
588y
42x+588y
Therefore 42x-56 is NOT EQUIVALENT to 42(x + 14y) but is equivalent to 42+588y
Answer:
The slope is -4 over -5
Step-by-step explanation:
Your equation should be y2-y1 over x2-x1. At first you will get -8 over -10 then you simplify and get -4 over -5
First, we separate all instances of t by subtracting J from both sides:
F = J + Jrt
F - J = Jrt
Then, we separate the t by dividing both sides by Jr:

Therefore, t is equal to (F - J) ÷ Jr