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USPshnik [31]
2 years ago
10

I HAVE 4 MATH QUESTIONS AND I REALLY NEED HELP FAST. PLEASE ONLY COMMENT IF YOU ARE GOING TO HELP. I GAVE AS MANY POINTS AS POSS

IBLE. ALSO PLEASE PUT RIGHT ANSWERS AND BE SERIOUS.

Mathematics
1 answer:
Andru [333]2 years ago
3 0
# 3 is 4 and # 4 is 1
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6 qts equals ? pints 8 qts equals ? gallons and 48 fl oz equals ? cups
nikdorinn [45]
6 quarts equals 12 pints
8 quarts equals 2 gallons
48 fl oz equals 6 cups
8 0
3 years ago
Read 2 more answers
If 2 sides of a triangle are 6 and 16, what is the range of the possible lengths of the third side?
Leno4ka [110]

Answer:

between 10 and 22

Step-by-step explanation:

A side of a triangle must measure between the difference of the lengths of the other two sides and the sum of the lengths of the other two sides.

Difference: 16 - 6 = 10

Sum: 6 + 16 = 22

Answer: between 10 and 22

6 0
3 years ago
Two planes that are traveling toward each other are 720 miles apart. One plane is traveling 40 miles per hour faster than the ot
natali 33 [55]

Answer:

y = 460 miles per hr

x = 500 miles per hr

Step-by-step explanation:

Let the planes be X any

Let their speeds be xmiles/hr and ymiles/hr respectively

x = y + 40 (assuming X is faster by 40miles/hr)

Distance travelled by X to meet Y = 0.75x

Distance travelled by Y to meet X = 0.75y

0.75x + 0.75y = 720 --------1

Put x = y + 40 in eqn 1

0.75(y+40) + 0.75y = 720

0.75y + 30 + 0.75y= 720

1.5y = 690

y = 460 miles per hr

x = 460 +40

= 500 miles per hr

7 0
2 years ago
Parabolas, hyperbolas, ellipses, and circles are all types of __________.
Harman [31]
<span>Parabolas, hyperbolas, ellipses, and circles are all types of (A) roulette's.</span>
4 0
3 years ago
A fireplace arch is to be constructed in the form of a semiellipse. The opening is to have a height of 3 feet at the center and
USPshnik [31]

Answer:

Step-by-step explanation:

Given

Fireplace is in the form of semi-ellipse  with height of 3 ft from center

Length of base=8 ft

if the arch is in the form of ellipse then it can be considered as horizontal ellipse with 2 a and 2 b be length of major and minor axis

2 a =8

a=4 ft

If contractor cover the whole base

then total length of string=2a =8 ft

(b)String should be nailed at focus

focus of ellipse is a e

where e=eccentricity

e=\sqrt{1-(\frac{b}{a})^2}

e=\sqrt{1-(\frac{3}{4})^2}=\frac{\sqrt{7}}{4}

Focus =ae =\sqrt{7}

Thus string should be nailed at 2.64 m from center

8 0
3 years ago
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