It looks like the ∩ sign may be missing from the question. If you mean to find A∩C, called the intersection, you're looking for elements that are both in A and C.
{0, 2} qualifies.
You have to solve this algebraicly.
To do this set up the proportion and add x to each term.
You get 4x and 7x
Set this equal to 33
4x+7x=33
Combine like terms and get 11x=33
Divide by 11
x=3
Now go back to 4x and 7x
Multiply them by x and get 12(4×3=12) and 21(7×3=21)
One group is 12 and the other is 21.
204 /6 = 34
29 +31 +33 + 35 +37 +39 = 207
4th number = 35
6(x + y) + (x - y)
<em>use distributive property</em>
= 6x + 6y + x - y
<em>combine like terms</em>
= (6x + x) + (6y - y)
<h3>= 7x + 6y</h3>
(9,-36)
X=9 Y= -36
-3x-9=1/3x-39
Solve it
The answer is x=9
Y=-3x-9
Y= -3(add the 9 because 9 is equal x) -9
Y=-3(9)-9
Solve it
The answer is y=-36
