If t(n) equals 3+2n, what is the 5th term?

A hiker is lost in the woods. A search team has created a coordinate grid to represent the woods. Each unit on the grid is one s

adelina 88 [10]

Since the hiker can move in any direction, the equation that represent the area in which the hiker could be will be the equation of circle with radius r=12 and center (5,10)
The equation of a circle with radius r and center (h,k) is:
$(h-x) ^{2} +(y-k) ^{2} =r ^{2}$
The only thing we have left is replace the values to get:
$(x-5) ^{2} +(y-10) ^{2} =12 ^{2}$
$(x-5) ^{2} +(y-10) ^{2} =144$

5 0

3 years ago

Read 2 more answers

1. Order the steps to show how to solve the equation2(4x − 11) + 9 = 19

-BARSIC- [3]

Answer:

Question: 1

 Subtract 9 from each side.

 Divide each side by 2

 Add 11 to each side.

 Divide each side by 4

Question: 2

10x +2 = 32

10x = 30

x = 3

Question: 3

19 -4c = 17

-4c = -2

c = 1/2 or 0.5

Question 4:

1.1x + 1.2x -5.4 = -10

2.3x = -4.6

x = -2

Question: 6

6(5 − 8v) + 12 = −54

6( 5 - 8v ) = -66

( 5 - 8v ) = -11

-8v = -16

v = 2

Step-by-step explanation:

8 0

3 years ago

22 points Please Help!!

Greeley [361]

Answer:

b

Step-by-step explanation:

3 0

3 years ago

4. Let B = {(1,0,1),(0,1,2), (2, -1,0)}. (a) The vectors in B are dependent. Show this. (b) Find a non-trivial solution to an(1,

Vladimir79 [104]

Answer:

Step-by-step explanation:

Given are three vectors in set B.

To show that B is dependent

The determinant

$\left[\begin{array}{ccc}1&0&1\\0&1&2\\2&-1&0\end{array}\right] \\=1(2)-1(2) =0$

Hence vectors are dependent

b) The given equation $a_1(1,0,1) + a_2(0,1,2) + a_3(2, -1,0) = 0.\\$

Let us try parametrically

These 3 vectors are collinear and hence equation would be

$\frac{x-1}{0-1} =\frac{y-0}{1} =\frac{z-1}{2-1} =s\\(x,y,z) = (1-s, s, 1+s)$

c) Basis for B would be only 2 dimensional

i.e. any two vectors out of 3 form basis

The basis would be (1,0,1) and (0,1,2)

3 0

3 years ago

The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. The follow

kipiarov [429]

Answer:

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

Step-by-step explanation:

The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. Test if the mean cost has increased.

At the null hypothesis, we test if the mean cost is still the same, that is:

$H_0: \mu = 13252$

At the alternative hypothesis, we test if the mean cost has increased, that is:

$H_1: \mu > 13252$

The test statistic is:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

13252 is tested at the null hypothesis:

This means that $\mu = 13252$

The following year, a random sample of 20 two-year institutions had a mean of $15,560 and a standard deviation of $3500.

This means that $n = 20, X = 15560, s = 3500$

Value of the test statistic:

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{15560 - 13252}{\frac{3500}{\sqrt{20}}}$

$t = 2.95$

P-value of the test and decision:

The p-value of the test is found using a t-score calculator, with a right-tailed test, with 20-1 = 19 degrees of freedom and t = 2.95. Thus, the p-value of the test is 0.0041.

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

7 0

3 years ago