4 years ago

Calculus Question, just the first line. Other stuff is just my work...

Mathematics

1 answer:

aleksandr82 [10.1K]4 years ago

8 0

What are you even asking us

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sergeinik [125]

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15.66

Step-by-step explanation:

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3 years ago

I need help solving the problem

geniusboy [140]

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ICE Princess25 [194]

Step-by-step explanation:

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3 years ago

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Vlad [161]

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3 years ago

Select the two values of x that are roots of this equation. x^2+2x-4=0

GuDViN [60]

Answer:

$\large\boxed{x=-1\pm\sqrt5}$

Step-by-step explanation:

$x^2+2x-4=0\qquad\text{add 4 to both sides}\\\\x^2+2x=4\\\\x^2+2(x)(1)=4\qquad\text{add}\ 1^2=1\ \text{to both sides}\\\\\underbrace{x^2+2(x)(1)+1^2}=4+1^2\qquad\text{use}\ (a+b)^2=a^2+2ab+b^2\\\\(x+1)^2=5\to x+1=\pm\sqrt5\qquad\text{subtract 1 from both sides}\\\\x=-1\pm\sqrt5$

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3 years ago