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sashaice [31]
3 years ago
5

the brightness of the illumination of an object varies inversely as the square of the distance from the object to the source of

light. how far from the bulb does an object receive four times as much illumination as it does when it is 8 m from the bulb
Mathematics
1 answer:
Andre45 [30]3 years ago
5 0
I=k/d^2

4=k/d^2 and 1=k/64  so if we divide the first by the second we get:

4/1=(k/d^2)/(k/64)

4=(k/d^2)*(64/k)

4=64/d^2

d^2=64/4

d^2=16

d=4 meters


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What is an equation of the line that passes through the point (3,6)(3,6) and is parallel to the line 4x-3y=214x−3y=21?
polet [3.4K]

<em><u>Question:</u></em>

What is an equation of the line that passes through the point (3,6) and is parallel to the line 4x-3y=21

<em><u>Answer:</u></em>

<em><u>The equation of the line that passes through the point (3,6) and is parallel to the line 4x-3y=21 is:</u></em>

y = \frac{4}{3}x + 2

<em><u>Solution:</u></em>

Given that line passes through the point (3,6) and is parallel to the line 4x-3y=21

<em><u>The equation of line in slope intercept form is given as:</u></em>

y = mx + c ------- eqn 1

Where, "m" is the slope and "c" is the y intercept

<em><u>Given equation is:</u></em>

4x - 3y = 21

Rearrange,

3y = 4x - 21

y = \frac{4}{3}x - \frac{21}{3}\\\\y = \frac{4}{3}x - 7

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m = \frac{4}{3}

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<em><u>Substitute m = 4/3 and (x, y) = (3, 6) in eqn 1</u></em>

6 = \frac{4}{3} \times 3 + c\\\\6 = 4 + c\\\\c = 2

<em><u>Substitute c = 2 and m = 4/3 in eqn 1</u></em>

y = \frac{4}{3}x + 2

Thus the equation of line is found

4 0
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gayaneshka [121]

Answer:

See below

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Let me know if you need more examples or have any questions :)

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