Answer:
The answer is
<h2>

</h2>
Step-by-step explanation:
Equation of a line is y = mx + c
where
m is the slope
c is the y intercept
To find the equation of the parallel line we must first find the slope of the original line
That's
Slope of the through points
(15, -6) and (-3, 13) is
<h3>

</h3>
Since the lines are parallel their slope are also the same
So slope of parallel line = - 19/18
Equation of the line using point (4,2) and slope -19/18 is
<h3>

</h3>
We have the final answer as
<h3>

</h3>
Hope this helps you
Answer:
the answer is d
Step-by-step explanation:
Just multiply and divide
So the mean is 72.97
We need to subtract the mean from each value and square it.
(65-72.97)^2= 63.5209
(68-72.97)^2=24.7009
(69-72.97)^2=15.7609
(70-72.97)^2=8.8209
(71-72.97)^2= 3.8809
(72-72.97)^2=0.9409
(90-72.97)^2=290.0209
(95-72.97)^2=485.3209
Now we add up the new values ( also consider their frequency) and find their mean.
Add the values
63.5209+(2 •24.7009=49.4018)+(5•15.7609=78.8045)+(8•8.8209=70.5672)+(7•3.8809=27.1663)+(3•0.9409=2.8227)+(2•290.0209=580.0418)+(2•485.3209=970.6418)= 1,842.967
Divide by total numburs to find the mean
1,842.967/ 30=61.43223333
The standar deviation is the square root of the mean so is
Square root of 61.43223333=7.837871735
Round to the nearest tenth
Standard Deviation is 7.8
Answer:
2
5

Step-by-step explanation:
We are given 2 fractional numbers:

We have to use fraction strips to compare to the fractional numbers.
Let we are Comparing
with the length of
number of
sections.
i.e.

Let we are Comparing
with the length of
number of
sections.
i.e.

Now, let us have a look at 3rd part of question:
The sections of 2/4 is _____ the length of 5/8. Therefore, 2/4 < 5/8
Let the answer be
.
So, the equation becomes:

So, the answers are:
2
5

To find how long it would take him, one has to divide 400 by 160 and then multiply 5 by what that number is. You multiply 5 by the quotient because that is the number that would make it proportional. 400/160 x 5 is 12.5, meaning that the answer is 12.5 minutes, or A.