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hodyreva [135]
3 years ago
8

H(x)=4|x+4|+3 what’s the answer

Mathematics
1 answer:
MatroZZZ [7]3 years ago
4 0

Answer:

To find the transformation, compare the two functions and check to see if there is a horizontal or vertical shift, reflection about the x-axis, and if there is a vertical stretch.

Parent Function:

g(x)=|x|

Horizontal Shift: Right 4 Units

Vertical Shift: Up 1 Units

Reflection about the x-axis: None

Vertical Compression or Stretch: None

Step-by-step explanation:

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Ray BD bisects ∠ABC so that m∠ABD = 5y – 3 and m∠CBD = 2y +12. Find the value of y.
myrzilka [38]

keeping in mind that an angle bisector cuts an angle into two equal angular halves.

check the picture below

8 0
3 years ago
Plz tell me this solution it's very urgent​
a_sh-v [17]

Step-by-step explanation:

here is fig 15

x=36 (v.o.a are equal)

36+y=180

y=180-36=144

y=z=144 vertically

3 0
3 years ago
14. Find the distance between (7,217pi/180 ) and (5,-23pi/36 ) on the polar plane.
irina [24]

Answer: the distance is  3.49 units

Step-by-step explanation:

There are some ways to find the exact distance, i will calculate the distance in rectangular coordinates.

When we have a point (R, θ) in polar coordinates, we can transform it into rectangular coordinates as:

x = R*cos(θ)

y = R*sin(θ)

Then we have:

(7,217pi/180 )

R = 7

θ = (217/180)*pi

x = 7*cos( (217/180)*pi) = -5.59

y = 7*sin( (217/180)*pi) = -4.21

So this point is (-5.59, -4.21) in rectangular coordinates.

And the other point is  (5,-23pi/36 )

R = 5

θ = -(23/36)*pi

x = 5*cos(  -(23/36)*pi ) = -2.11

y = 5*sin(  -(23/36)*pi ) = -4.53

So this point is (-2.11, - 4.53)

Then the point distance between those points is:

D = I (-2.11, -4.53) - (-5.59, -4.21) I

D = I (-2.11 + 5.59, -4.53 + 4.21) I

D = I (3.48, -0.32) I = √( (3.48)^2 + (-0.32)^2) =  3.49

4 0
3 years ago
Find the relative extrema, if any, of the function. Use the Second Derivative Test if applicable. (If an answer does not exist,
belka [17]

Answer:

We have the function g(x) = x^3 -15*x

First, to find extrema, we can find the zeros of the first derivative.

g'(x) = 3*x^2 -15

g'(x) = 0 = 3*x^2 - 15

x^2 = 15/3 = 5

x = √5

x = -√5

Now, watching at the second derivative we have:

g''(x) = 6*x

so when we have

g''(√5) = 6*√5 > 0 then x = √5 is a local minimum

g''(-√5) = -6*√5 < 0, then x = -√5 is a local maximum.

3 0
3 years ago
Henry is making a recipe for biscuits. A recipe calls for 5/10 kilogram flour and 9/100 kilogram sugar .
Alchen [17]
59/100 or 0.59.
Hope I helped!
~ Zoe
6 0
3 years ago
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