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Gnoma [55]
4 years ago
7

Jada is standing 10 feet away from the base of the tree and spots a nest sitting on a branch. The angle of elevation from the gr

ound where she is standing to the nest is 55 degrees. Find the height of the nest.

Mathematics
1 answer:
expeople1 [14]4 years ago
4 0

Answer:

14.3 feet

Step-by-step explanation:

Let the height of the tree = x feet.

It is given that the horizontal distance from the base of tree = 10 feet and the angle of elevation to the nest is 55°.

So, we get the following figure.

As, we are obtaining a right angled triangle.

Using the trigonometric form for the angles of a right angled triangle, we get,

\tan x=\frac{opposite}{adjacent}

i.e. \tan 55=\frac{x}{10}

i.e. x=10\times \tan 55

i.e. x=10\times 1.43

i.e. x=14.3

Hence, the height of the tree is 14.3 feet.

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Drag and drop question I need help on ASAP
klasskru [66]

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3 0
3 years ago
In the cafeteria, 80 juice boxes were put out for breakfast. After breakfast, there were 20 juice boxes left.
olchik [2.2K]

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Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Use the data set to determine which statements are correct. Check all that apply. 35, 41, 18, 75, 36, 21, 62, 29, 154, 70 The me
stepladder [879]
The median is 38.5

The lower quartile is 29

There is an outlier  (154)

The upper quartile is 70 
and
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4 0
4 years ago
Two cars start out together from the same place. they travel in opposite​ directions, with one of them traveling 5 miles per hou
Mashutka [201]
<u>Annotation</u>
General formula for distance-time-velocity relationship is as following
d = v × t
The velocity of the first car will be v₁, the time is 2 hours, the distance will be d₁.
The velocity of the second car will be v₂, the time is 2 hours, the distance will be d₂.


One of them traveling 5 miles per hour faster than the others. That means the velocity of the first car is 5 miles per hour more than the velocity of the second car.
v₁ = v₂ + 5  (first equation)

The distance of the two cars after two hours will be 262 miles apart. Because they go to opposite direction, we could write it as below.
d₁ + d₂ = 262 (second equation)

Plug the d-v-t relationship to the second equation
d₁ + d₂ = 262
v₁ × t + v₂ × t = 262
v₁ × 2 + v₂ × 2 = 262
2v₁ + 2v₂ = 262

Plug the v₁ as  (v₂+5) from the first equation
2v₁ + 2v₂ = 262
2(v₂ + 5) + 2v₂ = 262
2v₂ + 10 + 2v₂ = 262
4v₂ + 10 = 262
4v₂ = 252
v₂ = 252/4
v₂ = 63
The second car is 63 mph fast.

Find the velocity of the first car, use the first equation
v₁ = v₂ + 5
v₁ = 63 + 5
v₁ = 68
The first car is 68 mph fast.

Answer
\boxed{\boxed{ v_{1}=68mph} }
\boxed{\boxed{ v_{2}=63mph} }
7 0
4 years ago
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