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ella [17]
3 years ago
5

_______ has been defined as the process of identifying consumers with similar attributes who are likely to exhibit a similar buy

ing behavior. Group of answer choices Global market segmentation Globalization Demographics Positioning
Business
1 answer:
Hoochie [10]3 years ago
8 0

Global market segmentation has been defined as the process of identifying consumers with similar attributes who are likely to exhibit a similar buying behavior.

<h3><u>Explanation:</u></h3>

The process involved in the identification of a particular segment of customers to sell the products refers to the Global Market Segmentation. Those customers of the groups that has the nature of similar behavior in buying of certain products will be grouped together under this process.

The people in the identified group will have the same purchasing behavior. Thus, when the customers of similar buying behaviors are grouped then the targeting process of the business will become easier. Fir example if you are manufacturing chocolates then it will be easier to target on;ly children and the adults.

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3 years ago
According to U.S. law, a company has an illegal monopoly when it dominates an industry and ___. *
aivan3 [116]

Answer:

a

Explanation:

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2 years ago
Read 2 more answers
If the required reserve ratio is 2.50 percent, what is the monetary multiplier? if the monetary multiplier is 5, what is the req
ludmilkaskok [199]

If the required reserve ratio is 2.50 percent, the monetary multiplier is 40.

The money multiplier gives us the ratio of deposits to reserves (i.e. 1/R). That means, if the reserve ratio is 2.50% (i.e. 0.025), the money multiplier is 40 (i.e. 1/0.025). Thus, an initial deposit of USD 1,000 will end up creating a total of USD 40,000 in new money.

If the monetary multiplier is 5, the required reserve ratio is 20%.

Playing with the original multiplier formula, we can derive that R=1/m (m is money multiplier). If the money multiplier is 5, then the reserve ratio is 20% (i.e. 1/5 or 0.20).

8 0
3 years ago
Casey Nelson is a divisional manager for Pigeon Company. His annual pay raises are largely determined by his division’s return o
baherus [9]

Answer:

NPV: $180,285.49

IRR: 21.336%

simple rate of return: 72.13%

Explanation:

6,100,000 investment

contribution margin 3,000,000

fixed expense:       <u>     900,000  </u>

EBITA                         2,100,000

We will calculate the NPV without the depreciation, as the depreciation is the distribution of the investment cost over the project life.

If we include the depreciation we will be counting the investment amount twice. Entirely at Time 0  and then subtracting on each cash inflow.

We will calculate the NPV at 20% as is the company's discount rate. Even if the current division returns are in 24% as the company accepts project which yields 20%.

C \times \frac{1-(1+r)^{-time} }{rate} = PV\\

C 2,100,000

time 5 years

rate 20% = 20/100 = 0.2

2100000 \times \frac{1-(1+0.2)^{-5} }{0.2} = PV\\

PV $6,280,285.49

NPV = PV of cash inflow - investment

6,280,285.49 - 6,100,000 = 180,285.49

<u>the IRR:</u>

The internal rate of return is the rate at which the NPV of a priject is zero.

We calculate this using excel formula IRR

or a financial calculator

it could also be done with trial and error using the PV tables.

<u>I will explain you in Excel</u>

FIrst, you write the inflow and outflow per year:

-6,100,000

2,100,000

2,100,000

2,100,000

2,100,000

2,100,000

then we write on another cell:

=IRR(

then, select the cells

and press enter

21.336%

<u>the simple rate of return:</u>

(total return - investment) / investment

(2,100,000 x 5 - 6,100,000) / 6,100,000 =

4,400,000 / 6,100,000 = 0.721311475 = 72.13%

7 0
3 years ago
The following transactions and adjusting entries were completed by Robinson Furniture Co. during a three-year period. All are re
riadik2000 [5.3K]

Answer:

<u>Year 1 </u>

Jan. 8. Purchased a used delivery truck for $24,000, paying cash.

  • Dr Truck 24,000
  •     Cr Cash 24,000

Mar. 7. Paid garage $900 for changing the oil, replacing the oil filter, and tuning the engine on the delivery truck.

  • Dr Maintenance expenses - Truck 900
  •     Cr Cash 900

Dec. 31. Recorded depreciation on the truck for the fiscal year. The estimated useful life of the truck is four years, with a residual value of $4,000 for the truck.

Depreciation expense = 2 x 0.25 x $24,000 = $12,000

  • Dr Depreciation expense 12,000
  •     Cr Accumulated depreciation - truck 12,000

<u>Year 2 </u>

Jan. 9. Purchased a new truck for $50,000, paying cash.

  • Dr Truck new 50,000
  •     Cr Cash 50,000

Feb. 28. Paid garage $250 to tune the engine and make other minor repairs on the used truck.

  • Dr Maintenance expenses - Truck 250
  •     Cr Cash 250

Apr. 30. Sold the used truck for $9,500. (Record depreciation to date in Year 2 for the truck.)

depreciation expense = 2 x 0.25 x 4/12 x $12,000 = $2,000

  • Dr Depreciation expense 2,000
  •     Cr Accumulated depreciation - truck 2,000

truck sold at $9,500 - $10,000 (carrying value) = -$500 loss on sale

  • Dr Cash 9,500
  • Dr Accumulated depreciation 14,000
  • Dr Loss on sale - truck 500
  •     Cr Truck 24,000

Dec. 31. Record depreciation for the new truck. It has an estimated residual value of $12,000 and an estimated life of eight years.

Depreciation expense = 2 x 0.125 x $50,000 = $12,500

  • Dr Depreciation expense 12,500
  •     Cr Accumulated depreciation - truck new 12,500

<u>Year 3 </u>

Sept. 1. Purchased a new truck for $58,500, paying cash.

  • Dr Truck three 58,500
  •     Cr Cash 58,500

Sept. 4. Sold the truck purchased January 9, Year 2, for $36,000. (Record depreciation to date for Year 3 for the truck.)

Depreciation expense = 2 x 0.125 x 8/12 x $37,500 = $6,250

  • Dr Depreciation expense 6,250
  •     Cr Accumulated depreciation - truck new 6,250

truck sold at $36,000 - $31,250 (carrying value) = $4,750 gain on sale

  • Dr Cash 36,000
  • Dr Accumulated depreciation 18,750
  •     Cr Truck new 50,000
  •     Cr Gain on sale - truck new 4,750

Dec. 31. Recorded depreciation on the remaining truck. It has an estimated residual value of $16,000 and an estimated useful life of 10 years.

Depreciation expense = 2 x 0.1 x 4/12 x $58,500 = $3,900

  • Dr Depreciation expense 3,900
  •     Cr Accumulated depreciation - truck three 3,900
5 0
3 years ago
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