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andrew11 [14]
4 years ago
12

How to express 24.357 in unit form

Mathematics
1 answer:
bogdanovich [222]4 years ago
4 0
(2 × 10) + (4 × 1) + (3 × 1/10) + (5 × 1/100) +
(7 × 1/1000)
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A^½ха^2/3/a^3/5<br> I need help<br> P
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Answer:

15 sqrt a ^4

Step-by-step explanation:

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2 years ago
I need help with my homework can anyone help me please?
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For 14 from left to right should be 11 10 10 9 8 6. For 15 is wrong because 4 people jumped 3 feet and 3 people jumped 4 feet

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3 years ago
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Alice wants to make a fruit salad using 10 pieces of fruit. She can buy three types of fruits at the supermarket: Apples (A), Ba
sasho [114]

Answer:

There is a total of 66 different fruit salads.

Step-by-step explanation:

One fruit salad differs from the other only in the amount of pieces of certain fruit put in it. In order to easier denote fruit pieces we introduce these notations:

A-how many apples are put into the salad;

B-how many bananas are put into the salad;

C-how many cranberries are put into the salad.

Since she can freely choose the number of pieces of each fruit, we have these conditions for the variables A, B and C:

  1.   0\leq A\  ,\  0\leq B\  ,\  0\leq C  (she cannot choose a negative number of pieces)
  2. \ A\ ,\  B\ ,\  C\ \leq 10  (because she can get the total of 10 pieces of fruit)

Another condition for forming the salad is that the salad must consist of exactly 10 pieces of fruit, hence we have this equation to solve:

A+B+C=10

but we must obtain the non-negative integer solutions of this equation.

That is equivalent to calculating the number of r-combinations of the multi-set S with objects of k different types with infinite repetition numbers.

The formula for obtaining the number of such r-combinations is:

{r+k-1\choose r}={r+k-1\choose k-1}

We have that k=3 and that r=10 and we can observe the repetition number as infinite since she can create a fruit salad with only one piece of fruit and the repetition number in such cases is the maximum 10. Finally, we have that the total number of fruit salads equals:

{10+3-1\choose 10}={12\choose 10}=\frac{12!}{10!\cdot (12-10)!}=\frac{12\cdot 11\cdot 10!}{10!\cdot 2!}=\frac{132}{2}=66 .

8 0
3 years ago
WILL GIVE BRAINLYEST AND A LOT OF POINTS HELPPPPPP NOW Use the coordinate grid to determine the coordinates of point P:
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Answer:

d.

Step-by-step explanation:

next time take a deep breath

3 0
4 years ago
The area of the rhombus is 540 cm2; the length of one of its diagonals is 4.5 dm. What is the distance between the point of inte
malfutka [58]

1. The area of the rhombus can be found by the formula

A=\dfrac{d_1\cdot d_2}{2}, where d_1,\ d_2 are rhombus's diagonals.

Note that d_1=4.5\ dm=45\ cm, then

540=\dfrac{45\cdot d_2}{2},\\ \\540\cdot 2=45d_2,\\ \\d_2=24\ cm.

2. The diagonals of rhombus are perpendicular and are bisectors of each other. Then the triangle formed with halfs of diagonals is right triangles with legs

\dfrac{d_1}{2}=22.5\ cm,\ \dfrac{d_2}{2}=12\ cm.

The hypotenuse of this triangle is the rhombus's side. By the Pythagorean theorem

\text{rhombus's side}^2=(22.5)^2+12^2=506.25+144=650.25,\\ \\\text{rhombus's side}=25.5\ cm.

3. The distance between the point of intersection of the diagonals and the side of the rhombus is the height of right triangle considered above.

Use twice the Pythagorean theorem to find this height:

\left\{\begin{array}{l}x^2+h^2=12^2\\(25.5-x)^2+h^2=22.5^2,\end{array}\right.

where x is projection of leg 12 cm and h is height.

Subtract the first equation from the second:

(25.5-x)^2+h^2-x^2-h^2=22.5^2-12^2,\\ \\650.25-51x=506.25-144,\\ \\51x=650.25-362.25=288,\\ \\x=\dfrac{96}{17}\ cm.

Then

h^2=144-\left(\dfrac{96}{17}\right)^2=144-\dfrac{9216}{289}=\dfrac{32400}{289},\\ \\h=\dfrac{180}{17}\ cm.

Answer: h=\dfrac{180}{17}\ cm.

7 0
3 years ago
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