Answer:
4.
l=22cm
b:16cm
h:10cm
surface area =2(lb+bh+lh)=2(22*16+16*10+22*10)
=1464cm²
5.
a=2.5dm
area cubical soda cracker box=6a²=6*2.5²=37.5dm²
6.
r=1.5dm
area of ball=4πr²=4π×1.5²=28.27dm² per ball
for 10 bal =28.27×10=282.6dm²
Answer:
Probability of atleast one of 12 student has food allergies ≈ 0.58 ( approx)
Step-by-step explanation:
Given: Probability of a children under age 5 has food allergies = 7%
=
To find : Probability of atleast one of 12 student has food allergies
Probability of a chindren under age 5 does not have food allergies = 
⇒ prob = 
now we find Probability of atleast one of 12 student has food allergies this means we have to find prob of 1 student, 2 student, 3 student, till 12 student have allergy out of 12 student of class then add all prob.
But instead of finding all these probability we find probability of student having no allergy.i.e., 0 student then subtract it from 1(total probability)
Probability of 0 student having allergy out of 12 student = 
Therefore, Probability of atleast one of 12 student has food allergies
= 
= 
≈ 0.58 ( approx)
Answer:
inspector" (and any subsequent words) was ignored because we limit queries to 32 words.
Step-by-step explanation:
hope this is correct!
Let U = {1, 2, 3, 4, 5, 6, 7}, A= {1, 3, 4, 6}, and B= {3, 5, 6}. Find the set A’ U B’
Art [367]
Answer:
Step-by-step explanation:
A'={2,5,7}
B'={1,2,4,7}
A'UB'={1,2,4,5,7}
Step 1: simplify
[3.4 ( 6 x + 2 ) +3] + 4 p -3 x
Pemdas!
6x+2=8x
3.4+3=6.4
6.4+8x=14.4
14.4x+4p=18.4xp+3= 21.4xpx
x=8
p=18.4
Other x = 21.4