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Tcecarenko [31]
3 years ago
8

Can someone help me? Please :/

Mathematics
1 answer:
Liula [17]3 years ago
4 0

I hope this picture helps you a little bit!

If you don't understand, I'll try to explain more :)

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Explain how to estimate 586 - 321 two different ways
murzikaleks [220]
<span>To estimate 586 - 321, you can round the numbers up or down to the nearest five.
586 can either become 570, rounding up, or 585, rounding down, which is closer. 321 becomes 320. It's not close enough to 325, nor to 315, for either of those to be good choices. 570 - 320 = 250 and 585 - 320 = 265. The actual solution to the original problem is 265, so, the second estimate, because they both go down by 1, is the closest.</span>
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4 years ago
Use the graphing calculator to determine the interval on which the inequality log2 (0.7x) log3(3x – 1) is true. Round any decima
Elina [12.6K]

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[0.373, 16.607]

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4 years ago
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What was the average speed of a car that drove 340.2 miles in 4.2 hours?
hoa [83]

The answer is <em>81 mph</em>. If you <em>divide</em> <em>340.2 and 4.2 </em>the <em>quotient</em> will be 81.

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4 years ago
Are these triangles similar or no?
Marrrta [24]
Yes these triangles are similar

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4 years ago
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What is the solution to log2(2x^3-8)-2log2x=log2x?
Alexxandr [17]

Answer:

<h2>x = 2</h2>

Step-by-step explanation:

\\\\\text{Domain:}\\\\2x^3-8>0\ \wedge\ x>0\\2x^2>8\to  x^3>4\to x>\sqrt[3]4\\\\x\in(\sqrt[3]{4},\ \infty)\\\\\log_2(2x^3-8)-2\log_2x=\log_2x\qquad\text{add}\ 2\log_2x\ \text{to both sides}\\\\\log_2(2x^3-8)=3\log_2x\qquad\text{use}\ n\log_ab=\log_ab^n\\\\\log_2(2x^3-8)=\log_2x^3\iff2x^3-8=x^3\qquad\text{subtract}\ 2x^3\ \text{from both sides}\\\\-8=-x^3\qquad\text{change the signs}\\\\8=x^3\to x=\sqrt[3]8\\\\x=2\in D

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3 years ago
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