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Sloan [31]
3 years ago
5

Eliana takes photos and videos on her phone. Let P represent the number of photos and V represent the number of videos that Elia

na can take using her storage space. 15P+70V < 400, Eliana wants to take 12 photos. How many videos at most can she take with the remaining storage space?
Mathematics
2 answers:
Bad White [126]3 years ago
8 0

Answer:

She can take at most 3 videos.

Step-by-step explanation:

Here, P represent the number of photos and V represent the number of videos that Eliana can take using her storage space.

Also, the given inequality that shows this situation is,

15P+70V < 400------(1)

If Eliana wants to take 12 photos.

⇒ P = 12,

From inequality (1),

15\times 12+70V

180+70V

70V

70V

V

Since, the number of videos must be whole number,

Hence, the maximum number of videos she can take is 3. ( By the above inequality )

qaws [65]3 years ago
5 0

P = 12.

So,

15(12) + 70V < 400

V < (400 - 180)/17

V <3.14

So the max number of video can fit is 3.

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Yanka [14]

Answer:

72

Step-by-step explanation:

cross out 4 from left to right, right to left, you get 71 and 73, the mean of those two numbers is 72

3 0
3 years ago
PLEASE HELPPP MEEEEE
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Answer:

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7 0
3 years ago
PLEASE HELP ASAP!! CORRECT ANSWER ONLY PLEASE!!<br><br> What is the expression in radical form?
Charra [1.4K]

(4x^{3}y^{2})^\frac{3}{10} =\sqrt[10]{4^{3}x^{9}y^{6}} =\sqrt[10]{64x^{9}y^{6}}

7 0
3 years ago
5v^2 -- 30v + 40<br> Factoring polynomials
Valentin [98]

First let's factor a 5 from every term.

5v^2-30v+40

=5(v^2-6v+8)

The v^2-6x+8 can be further factored using the x method(as I call it, its not its official name of course), You can get

5(v^2-6v+8)

=5(v-2)(v-4)

Done! any questions just ask in the comment section.

**Edit: You needed the area model so here is how it goes, I cannot draw lines but I will try my best.

we have original equation 5v^2-30v+40

first simplify to 5(v^2-6v+8)

Now factor the second part but using area model.

         v          -2

    _____________

v    |    v^2   |     -2v    |

    --------------------------

-4   |   -4v  |     8      |

      _____________

This is basically the area model the thing in the middle is suppose to be a rectangle split into 4 parts and then the numbers on top and left are suppose to be the factored equations while they multiplies to the number in the box.

<u>Is this efficient?</u>

Definitely not, it took me longer to draw the box than write my whole first explanation.

<u>Is this easy?</u>

No, again it took me about 170 times longer to think of this answer this way.

<u>Should you use this method?</u>

Sure if your teacher wants you to, but just saying later in algebra these methods are way to slow and there are way better methods to factor, so if you arn't solid in the area model just don't worry about it.

4 0
3 years ago
Which expression is equivalent to 128x^5y^6 \ 2x^7y^5 ? Assume x &gt; 0 and y &gt; 0.
N76 [4]

Answer: Last option.

Step-by-step explanation:

Given the expression:

\sqrt{\frac{128x^5y^6}{2x^7y^5}

The Quotient of powers property states that:

\frac{a^m}{a^n}=a^{(m-n)}

And the Power of a powet property states that:

(a^m)^n=a^{mn}

Then, applying these properties, you get:

=\sqrt{\frac{(2^3)^26y}{x^2}

Now you must remember that:

\sqrt[a]{a^n}=a

Therefore, simpliying the expression, you get:

=\frac{2^3\sqrt{y}}{x}=\frac{8\sqrt{y}}{x}

7 0
3 years ago
Read 2 more answers
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