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umka2103 [35]
1 year ago
11

NEED HELP ASAP WILL MARK BRAINLIEST!

Mathematics
2 answers:
AlekseyPX1 year ago
7 0

Answer:

\boxed {1)log_{b}(75) = 4.317}

\boxed {2)ln(20) = 2.9957}

Step-by-step explanation:

\textsf {Question l :}

\longrightarrow \mathsf {log_{b}(3) = 1.099}

\longrightarrow \mathsf {log_{b}(5) = 1.609}

\textsf {Identities applied :}

\boxed {log(ab) = loga + logb}

\boxed {log(a)^{x} = xloga}

\textsf {We can rewrite the problem as :}

\longrightarrow \mathsf {log_{b}(75)}

\longrightarrow \mathsf {log_{b}(25 \times 3)}

\longrightarrow \mathsf {log_{b}(5^{2} \times 3)}

\longrightarrow \mathsf {log_{b}(5)^{2} + log_{b}(3)}

\longrightarrow \mathsf {2log_{b}(5) + log_{b}(3)}

\textsf {Now, substitute the values :}

\longrightarrow \mathsf {2(1.609) + (1.099)}

\longrightarrow \mathsf {3.218 + 1.099}

\longrightarrow \mathsf {4.317}

\boxed {log_{b}(75) = 4.317}

\textsf {Question ll :}

\longrightarrow \mathsf {ln(4) = 1.3863}

\longrightarrow \mathsf {ln(5) = 1.6094}

\textsf {Rewriting the problem :}

\longrightarrow \mathsf {ln(20)}

\longrightarrow \mathsf {ln(4 \times 5)}

\longrightarrow \mathsf {ln(4) + ln(5)}

\longrightarrow \mathsf {1.3863 + 1.6094}

\longrightarrow \mathsf {2.9957}

\boxed {ln(20) = 2.9957}

quester [9]1 year ago
5 0

Answer:

\sf \log_b(75)=4.317

\sf \ln (20)=2.9957

Step-by-step explanation:

<u>Question 1</u>

Given:

  \sf \log_b(3)=1.099

  \sf \log_b(5)=1.609

To evaluate \sf \log_b(75),  replace 75 with (5 × 5 × 3):

\implies \sf \log_b(5 \cdot 5 \cdot 3)

\textsf{Apply the Product log law}: \quad \log_axy=\log_ax + \log_ay

\implies \sf \log_b5+\log_b5+\log_b3

Substitute the given values to solve:

\implies \sf 1.609 + 1.609 + 1.099=4.317

<u>Question 2</u>

Given:

  \sf \ln(4)=1.3863

  \sf \ln(5)=1.6094

To evaluate ln(20) replace 20 with (4 × 5):

\implies \sf \ln (4 \cdot  5)

\textsf{Apply the Product log law}: \quad \ln xy=\ln x + \ln y

<em />\implies \sf \ln (4)+\ln (5)

Substitute the given values to solve:

\implies \sf 1.3863+1.6094=2.9957

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