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nika2105 [10]
3 years ago
9

1. Dorothy bought a teddy bear and sold it at a 20% profit to Kim. Kim bought a suit costing $100 and dressed the teddy bear up

in the suit. Kim then sold the teddy bear in the suit to Karen for $442. Kim made a profit of 30%. How much did Dorothy pay for the teddy bear?​ And why?
2. If x is less than y by 25%, then y is more than x by __%? And why?
Mathematics
1 answer:
makkiz [27]3 years ago
6 0

1. Dorothy paid $200 for the teddy bear

2. y is more than x by 33\frac{1}{3} %

Step-by-step explanation:

1. The given is:

  • Dorothy bought a teddy bear and sold it at a 20% profit to Kim
  • Kim bought a suit costing $100 and dressed the teddy bear up in the suit
  • Kim then sold the teddy bear in the suit to Karen for $442
  • Kim made a profit of 30%

We need to find how much Dorothy paid for the teddy bear

Assume that Dorothy bought a teddy bear for $x

∵ Dorothy bought a teddy bear for $x

∵ She sold it at a profit 20% to Kim

By using the ratio method

→  Buying price    :    Profit    :    Selling price

→  100%                 :   20%       :    120% ⇒ (100% + 20%)

→  x                         :                 :    ?

By using cross multiplication  

∴ 100% × Selling price = x × 120%

- Divide both sides by 100%

∴ Selling price = 1.2x

∴ Dorothy sold the teddy bear for $1.2x to Kim

∵ Kim bought a suit costing $100 and dressed the teddy bear

  up in the suit

∴ The cost of the teddy bear = 1.2x + 100

∵ Kim sold the teddy bear in the suit to Karen for $442

∵ Kim made a profit of 30%

By using the ratio method

→  Cost price    :    Profit    :    Selling price

→  100%             :   30%      :    130% ⇒ (100% + 30%)

→  1.2x + 100     :                 :    442

By using cross multiplication  

∴ (1.2x + 100) × 130% =  100% × 422

- Divide both sides by 130%

∴ 1.2x + 100 = 340

- Subtract 100 from both sides

∴ 1.2x = 240

- Divide both sides by 1.2

∴ x = 200

∴ Dorothy bought the teddy bear for $200

Dorothy paid $200 for the teddy bear

2. The given is:

  • x is less than y by 25%
  • Then y is more than x by how many percent

Assume that y is 100%

∵ y = 100%

∵ x is less than y by 25%

∴ x = 100% - 25%

∴ x = 75%

- The percentage of increasing of y = \frac{y-x}{x} × 100%

∵ The percentage of increasing of y = \frac{100-75}{75} × 100%

∴ The percentage of increasing of y = \frac{25}{75} × 100%

∴ The percentage of increasing of y = \frac{1}{3} × 100%

∴ The percentage of increasing of y = 33\frac{1}{3} %

y is more than x by 33\frac{1}{3} %

Learn more:

You can learn more about the ratio in brainly.com/question/4713715

#LearnwithBrainly

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Geologist has collected 10 specimens of basaltic rock and 10th specimens of granite. The geologist instructs a laboratory assist
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Answer:

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Step-by-step explanation:

If we have N elements with k elements that we consider success and N-k elements that we consider fail, and we take a sample of n elements, the probability that there are x successes in the sample follows a hypergeometric distribution, so it is calculated as:

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In this case, N is equal to 20, k is equal to 10 specimens of granite rock, N-k is equal to 10 specimens of basaltic rock and n is 15. So, the probability that there are x specimens of granite rock in the sample or the pmf of the number of granite specimens selected for analysis is:

p(x)=\frac{(10Cx)*((10)C(15-x))}{20C10}

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p(5)=\frac{(10C5)*((10)C(15-5))}{20C10}=0.00136

On the other hand, the probability that all specimens of one of the two types of rock are selected  for analysis is the probability to select 10 granite specimens or 10 basaltic specimens. Where the probability to take 10 basaltic specimens is equal to the probability to take 5 granite specimens.

Then, the probability that all specimens of one of the two types of rock are selected  for analysis is:

p(10)+p(5)=\frac{(10C10)*((10)C(15-10))}{20C10}+\frac{(10C5)*((10)C(15-5))}{20C10}\\p(10)+p(5)=0.00136+0.00136=0.00272

For the hypergeometric distribution, the mean E(x) and standard deviation S(x) are:

E(x)=\frac{nk}{N}=\frac{15*10}{20}=7.5\\S(x)=\sqrt{\frac{nk}{N}*(1-\frac{k}{N})*(\frac{N-n}{N-1})}\\S(x)=\sqrt{\frac{15*10}{20}*(1-\frac{10}{20})*(\frac{20-15}{20-1})}=0.9934

Then, the number of granite specimens within 1 standard deviation of its mean value is:

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7.5-0.9934 ≤ mean ≤ 7.5+0.9934

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