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riadik2000 [5.3K]

3 years ago

11

1. Give an example of a repeating decimal where two digits repeat. Explain why your number is a rational number.

1 answer:

zzz [600]3 years ago

7 0

1. A repeating decimal is a decimal number that eventually takes on a repeating pattern of digits after its decimal point that will continue forever. For example, 17.(23)=17.23232323232323....

2. A decimal number that has digits that do not go on forever is called terminating decimal. Any rational number (that is, a fraction in lowest terms) can be written as either a terminating decimal or a repeating decimal . Just divide the numerator by the denominator . If you end up with a remainder of 0, then you have a terminating decimal. Otherwise, the remainders will begin to repeat after some point, and you have a repeating decimal.

3. Repeating decimal between 0 and 1: 0.(987)=0.987987987987...

Terminating number between 0 and 1: 0.987

0.(987) >0.987.

4. When dividing 1 by 6 you can get 0.1666666666...=0.1(6).

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Ira Lisetskai [31]

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3 years ago

Read 2 more answers

Determine weather the following is real or complex <br> i^6-122-7i^2

Leona [35]

Answer:

Real

Step-by-step explanation:

i^6-122-7i^2

(i^2)^3-122-7i^2

(-1)^3-122-7×(-1)

-1-122+7

-123+7

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So the final answer is -116

7 0

3 years ago

Find an equation of the sphere that passes through the origin and whose center is (-2, 2, 3). Be sure that your formula is monic

Andrei [34K]

Answer:

$\bold{(x+2))^2+(y-2)^2+(z-2)^2=17}$

Step-by-step explanation:

Given the center of sphere is: (-2, 2, 3)

Passes through the origin i.e. (0, 0, 0)

To find:

The equation of the sphere ?

Solution:

First of all, let us have a look at the equation of a sphere:

$(x-a)^2+(y-b)^2+(z-c)^2=r^2$

Where ( $x,y,z$ ) are the points on sphere.

$(a, b, c)$ is the center of the sphere and

$r$ is the radius of the sphere.

Radius of the sphere is nothing but the distance between any point on the sphere and the center.

We are given both the points, so we can use distance formula to find the radius of the given sphere:

$D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}$

Here,

$x_1 =0 \\y_1 =0 \\z_1 =0 \\x_2 =-2 \\y_2 =2 \\z_2 =3$

So, Radius is:

$r = \sqrt{(-2-0)^2+(2-0)^2+(3-0)^2}\\\Rightarrow r = \sqrt{4+4+9} = \sqrt{17}$

Therefore the equation of the sphere is:

$(x-(-2))^2+(y-2)^2+(z-2)^2=(\sqrt{17})^2\\\bold{(x+2))^2+(y-2)^2+(z-2)^2=17}$

4 0

3 years ago

Is 8 a solution to 1/2x+9=13?

Viktor [21]

Answer:

yes

Step-by-step explanation:

solve for x by simplifying both sides of the equation, then isolating the variable.

x = 8

8 0

3 years ago

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Gemiola [76]

In a quadratic function you square x so I'd assume that's what they want.

That means the values of f(x) would be:

9

1

1

9

25

4 0

2 years ago