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3 years ago

Does anyone know how to do this?:)

Mathematics

2 answers:

svetoff [14.1K]3 years ago

6 0

Answer:

c = 24

Step-by-step explanation:

Solve for c by simplifying both sides of the equation, then isolating the variable.

torisob [31]3 years ago

5 0

Answer:

<h3>Answer</h3>

c=24

Step-by-step explanation:

you just have to do the process for solving c

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If Upper X overbar equals 62, Upper S equals 8, and n equals 36, and assuming that the population is normally distributed, c

marishachu [46]

Answer:

The 99% confidence interval would be given by (58.373;65.627)

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=62$ represent the sample mean

$\mu$ population mean (variable of interest)

s=8 represent the sample standard deviation

n=36 represent the sample size

Part a: Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=36-1=35$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,35)".And we see that $t_{\alpha/2}=2.72$

Now we have everything in order to replace into formula (1):

$62-2.72\frac{8}{\sqrt{36}}=58.373$

$62+2.72\frac{8}{\sqrt{36}}=65.627$

So on this case the 99% confidence interval would be given by (58.373;65.627)

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

3 0

4 years ago

how to solve this prroblem by marianne buys 16 bags of potting soil that come in 5÷8_pound bags .how many pounds of potting soil

barxatty [35]

So, she buys 16 bags, each of them weights $\frac{5}{8}$ pounds.

to find how many pounds of soil she bought, we have to multiply:

16* $\frac{5}{8}$ =//16 is equal to 8*2, so we can simpify:
2* $\frac{5}{1}$

which is 2*5=10

so in the end she bought 10 pounds of soil!

3 0

3 years ago

What are the coordinates of point BBB on \overline{AC} AC start overline, A, C, end overline such that the ratio of ABABA, B to

Nady [450]

I think it’s gonna be C

3 0

3 years ago

Read 2 more answers

A math teacher needs to choose 6 students from class of 30 to go to the library. How many different groups can she select?

Hunter-Best [27]

The answer is D. Divide 30 by 6 and get 5. Five is not a possible answer therefore the answer is D

7 0

4 years ago

What is the mean?<br><br> $5.25, $3.50, $4.50, $4.00 , $3.50

san4es73 [151]

Answer:

The answer to your question is: $4.15

Step-by-step explanation:

To find the mean we just have to sum all the values and divide them by the number of data.

mean = (5.25 + 3.50 + 4.50 + 4.00 + 3.50) / 5

mean = 20.75/5

mean = $ 4.15

7 0

4 years ago