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mihalych1998 [28]
3 years ago
14

Find the gradient of the function. Assume the variables are restricted to a domain on which the function is defined. z=2xe2yx+2y

. Enter an answer in each field. Enclose numerators and denominators in parentheses. For example, (a−b)/(1+n).
Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
4 0

Answer:

grad(z(x,y))=2[e^{2xy}+2xye^{2xy}]\hat{i}+[4x^{2}e^{2xy}+2]\hat{j}

Step-by-step explanation:

z=2xe^{2yx}+2y

The gradient of a function is

grad(z(x,y))=D_{x}z(x,y)\hat{i}+D_{y}z(x,y)\hat{j}

where Dx means derivative over x and the same for Dy. Hence we have

grad(z(x,y))=2[e^{2xy}+2xye^{2xy}]\hat{i}+[4x^{2}e^{2xy}+2]\hat{j}

where we have used derivative of a product anf of an exponential function

I hope this is useful for you

regards

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Help me on this one please
sashaice [31]

Answer:

I believe the answer would be 3, and 7.

Step-by-step explanation:

Here's why to start off (x-3)(x-7)=0

What would you plug into x to make it 0, well x=3, and x=7, because 3-3=0, 7-7=0


Hope this helped!!!, :)

6 0
3 years ago
Covert 7 pi over 5 to degrees
hjlf

Answer:

Step-by-step

To convert radians to degrees, multiply by 180π , since a full circle is 360° or 2π radians.

3 0
4 years ago
George is considering two different investment options. The first offers 7.4% per year simple interest on the initial deposit. T
pentagon [3]

Answer:

Part A) \$12,220.00

Part B) \$12,134.08

Part C) The simple interest investment is better than the compounded  interest investment at the end of three years.

Part D)  see the explanation

Step-by-step explanation:

Part A) Determine the value of the simple-interest investment at the end of three years

we know that

The simple interest formula is equal to

A=P(1+rt)

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

t=3\ years\\ P=\$10,000\\r=7.4\%=7.4/100=0.074

substitute in the formula above

A=10,000(1+0.074*3)

A=10,000(1.222)

A=\$12,220.00

Part B) Determine the value of the compound-interest investment at the end of three years

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=3\ years\\ P=\$10,000\\r=6.5\%=6.5/100=0.065\\n=4

substitute in the formula above

A=10,000(1+\frac{0.065}{4})^{4*3}  

A=10,000(1.01625)^{12}  

A=\$12,134.08

Part C) Which investment is better over the first three years?

Compare the two investment

\$12,134.08 < \$12,220.00

The compounded  interest investment is less than the simple interest investment

therefore

The simple interest investment is better than the compounded  interest investment at the end of three years

Part D) How would you advise George to invest his money if he is unsure how long he’ll keep the money in the account?

we have

A=10,000(1+0.074t)  ----> simple interest formula as a function of the time t

A=10,000(1.01625)^{4t}   ----> compound interest formula as function of the time t

Look to the attached graph below

The red line represents the simple interest investment

The blue curve represents the compounded interest investment

After 0 years and before 4.179 years the red line is over the blue curve, that means the simple interest is better because it gives more money than the compounded interest

After that the blue curve is over the red line that means the compounded quarterly is better because it gives more money than the simple interest

therefore

I advise George to invest his money in the compounded interest investment if he will keep the money for a long time

4 0
3 years ago
The points (0, 3), (4, 0), (9, 0), (0, 11), and (14, 0) are plotted on the graph. On a coordinate plane, points (0, 3), (4, 0),
Advocard [28]

Answer:

can you take a picture it might make it easier for me

3 0
3 years ago
Read 2 more answers
Which situation can be represented by 80x &gt; 150 + 50x?
V125BC [204]

Answer:

All numbers greater than 5, i.e., x>5 .

Step-by-step explanation:

The given inequality is  

80x>150+50x

Isolate variable terms on one side to find the solution.

Subtract  50x from both sides.

80x-50x>150+50x-50x

30x>150

Divide both sides by 30.

\dfrac{30x}{30}>\dfrac{150}{30}

x>5

It means, all the numbers which are greater than 5, are the solutions of the given inequality and 5 is not included in the solution set.

6 0
3 years ago
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