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3 years ago

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3x-2y=17 -4x-3y=17 HELP MEEE

2 answers:

Vinvika [58]3 years ago

6 0

Equation 1) 3x -2y = 17
Equation 2) -4x - 3y = 17

Multiply equation 1 by 3.

1) 3(3x - 2y = 17)
1) 9x - 6y = 51

Multiply equation 2 by 2.

2) 2(-4x - 3y = 17)

2) -8x - 6y = 34
1) 9x - 6y = 51

Subtract equations from each other.

-17x = -17

Divide both sides by -17.

x = 1

Plug in 1 for x in the first equation.

3x - 2y = 17

3(3) - 2y = 17

Simplify.

9 - 2y = 17

Subtract 9 from both sides.

-2y = 17 - 9

Simplify.

-2y = 8

Divide both sides by -2.

y = -4

x = 1, y = -4

~Hope I helped!~

lana [24]3 years ago

3 0

X=1 and y=-7
Hope this will help you!

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3 years ago

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Ilia_Sergeevich [38]

An object that is in motion as a projectile follows a path or trajectory of a parabola

The function and values are;

a) The equation of the quadratic function is; $\underline{y = \dfrac{111}{140} \cdot x - \dfrac{3}{140} \cdot x^2}$

b) The maximum height of the ball is approximately <u>7.334 m</u>

c) Horizontal distance at maximum height <u>18.8 meters</u>

<u />

Reason:

a) Known parameters are;

Let f(x) = a·x² + b·x + c represent the equation of the parabola modelling the path of the ball, we have;

Points on the path of the parabola = (0, 0), (35, 1.5), 37, 0)

Plugging the values gives;

0 = a·0² + b·0 + c

Therefore, c = 0

1.5 = 35²·a + 35·b

0 = 37²·a + 37·b

Solving gives;

a = -3/140, b = 111/140

The equation of the quadratic function is therefore;

$\underline{y = f(x) = \dfrac{111}{140} \cdot x - \dfrac{3}{140} \cdot x^2}$

b) The maximum height is given by the vertex of the parabola

The x-coordinate at the vertex is the point $-\dfrac{b}{2 \cdot a}$

Which gives;

$x-coordinate = \dfrac{\frac{111}{140} }{2 \times \dfrac{3}{140} } = 17.5$

The maximum height is therefore;

$f(x)_{max} = \dfrac{111}{140} \times 17.5 - \dfrac{3}{140} \cdot 17.5^2 \approx 7.334$

The maximum height of the ball is approximately 7.334 m

c) The distance the ball has travelled to horizontally is given by half of the range, <em>R</em> as follows;

The range of the motion, R = 37 meters

$Horizontal \ distance \ to \ maximum \ height = \dfrac{R}{2}$

Therefore;

$Horizontal \ distance \ to \ maximum \ height = \dfrac{37}{2} = 18.5$

The distance the ball has travelled horizontally to reach the maximum height horizontally <u>18.5 meters</u>

Learn more about the trajectory of a projectile here:

brainly.com/question/13646224

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ra1l [238]

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Step-by-step explanation: The next one is the same. 9•9=81 // 3 + 81= 84

Hope that helps!:) -Andi

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4 years ago