The total number of different outcomes of the toss are 256.
<u>Explanation:</u>
Given:
Coin is flipped 8 times.
Number of different outcomes, n = ?
A coin is flipped eight times where each flip comes up either
heads or tails.
Considering the order of the results from each toss does matter.
Each toss has two possibilities and the number of toss is 8.
Thus, the total outcome of the toss = 2⁸
n = 256
Therefore, total number of different outcomes of the toss are 256.
You don't list the "sums listed below" but I can still help you.
There are 6 ways to get a sum of 7 using a pair of dice:
1+6
6+1 You might be asking why 2+5 isn't the same as 5+2
2+5 Imagine the dice are different colors. Is a red 2 and green 5 the
5+2 same as a green 2 and red 5? (No, it's not)
3+4
4+3
You need two numbers that also provide 6 ways to win. One pair that would work is 11 and 9 There are two ways to make 11 (5+6) and (6+5) and there are four ways to make 9 (3+6), (6+3) (4+5) and (5+4) - that's a total of six ways. So to balance your friend's 7 - you could go for sums of 11's and 9's. Check the choices you were given and find the numbers (it could be three numbers like 2,3, and 12) that give you 6 ways to win.
Here are the numbers and their ways
Sum of the dice Ways to get it
2 1
3 2
4 3
5 4
6 5
7 6
8 5
9 4
10 3
11 2
12 1
Answer:
x=20
Step-by-step explanation:
64/8=8
The answer is 8 band members in each row
