Question

3 2 ? start fraction, 2, divided by, 3, end fraction of the doughnuts in a box have frosting. \dfrac12 2 1 ? start fraction, 1, divided by, 2, end fraction of the doughnuts with frosting have sprinkles. What fraction of the doughnuts in the box have frosting and sprinkles?

Answer 1

Answer:

$\frac{1}{3}$ of the doughnuts in the box have frosting and sprinkles.

Step-by-step explanation:

If there are $x$ doughnuts in the box. Then, $\frac{2}{3} \times x = \frac{2x}{3}$  of the doughnuts in the box have frosting. Therefore, $\frac{1}{2} \times \frac{2x}{3} = \frac{1}{3}x$ of the doughnuts with frosting have sprinkles. This implies that $\frac{1}{3}$ of the doughnuts in the box have frosting and sprinkles.