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Let x = number of 5 cent coins.
Then there are (x+2) 10 cent coins.
Let y = 20 cent coins.
Total coins: x+(x+2)+y = 30
2x+y=28
y = 28-2x (1)
Total value: 0.05x + 0.1(x+2) + 0.2y = 3.80
0.15x + 0.2y + 0.2 = 3.80
0.15x + 0.2y = 3.60 (2)
Substitute (1) into (2).
0.15x + 0.2(28-2x) = 3.60
-0.25x + 5.60 = 3.60
2.00 = 0.25x
8 = x
From (1), obtain y = 28 - 2(8) = 12
Answer: (x+2) = 8+2 = 10
Louise has 10 10-cent coins
You're question asks why the given mixed numbers are equal.
In fact, they're equal.
Lets make it easier for you to understand:
8 4/3 has a improper fraction "4/3", that fraction is over 1 whole.
You could look at 8 4/3 as:
8 + 3/3 + 1/3
The 3/3 turns into 1:
8 + 1 + 1/3
9 + 1/3
9 1/3
You would see that it turns into 9 1/3, therefore they are equal.
The approximate value of √191 to the nearest tenth is 13.8 and the two numbers that should fall on the number line is between 13-13.5.
Given that,
So, the approximate value of √191 is
= 13.8
It shows that the two numbers that should fall between at the time when place on the number line is between 13-13.5.
Therefore we can conclude that the approximate value of √191 to the nearest tenth is 13.8 and the two numbers that should fall on the number line are between 13-13.5.
Learn more about the number line here: brainly.com/question/16191404
OK so my answer is from what you’ve just explained that means you multiply the six and the 114 is 684 so that means if you have to do that to 13 of them that means 684×13 is what your equation would be in the answer to 684×13 is 8892
