The maximum revenue would be $9600 and would be achieved using 0 nonstop flights and 12 two-stop flights.
<h3>How to define the variables</h3>Let x = number of non-stop airplanes
Let y = number of two-stop airplanes
<h3>The system of linear inequalities</h3>Using the variables in (a), we have the following constraints
Total passenger constraint: 150x + 100y <= 1500
Total Airplanes constraint: x + y <= 12
<h3>Graph the feasible region.</h3>In (b), we have the following system of linear inequalities
150x + 100y <= 1200
x + y <= 12
See attachment for the graph
<h3>The objective function</h3>The objective function of the constraints is:
Max z = 1100x + 800y
<h3>The maximum revenue</h3>From the graph of the function, the optimal solution is:
(x,y) = (0,12)
So, the maximum revenue is:
z = 1100x + 800y
z = 1100*0 + 800*12
z = 9600
Hence, the maximum revenue is $9600
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