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Katarina [22]
3 years ago
13

Https://brainly.com/question/12057829 CAN SOMEONE TELL ME HOW TO GRAPH THIS

Mathematics
2 answers:
olga55 [171]3 years ago
6 0

we can draw the graph of cosine with amplitude 2.

Step-by-step explanation:

In the given function g(x) = 2cosx we know the following parameters which are helpful to draw the graph.

Its a cosine graph given in the form of y = acos(Bx + c) + d

Here a is amplitude, period = , c = phase shift, d = vertical shift

We know a = 2, B = , c = 0, d = 0.

GenaCL600 [577]3 years ago
6 0

Answer:

You graph it but

Step-by-step explanation:

Ghyyyyyy ya know it’s nottttt harddd lollipops

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I need help on this plZ
never [62]

Answer:

1. See the attached figure to this answer.

2. Lines A and B are parallel to each other.

3. Line Z is the transversal.

4. The same side interior angles are ∠ 4, ∠ 6 & ∠ 3, ∠ 5.

5. The alternate interior angles are ∠ 3, ∠ 6 & ∠ 4, ∠5

6. Corresponding angles are ∠ 1, ∠ 6 & ∠ 2, ∠ 5 & ∠ 3, ∠ 7 & ∠ 4, ∠ 8.

7. Alternate interior angles are ∠ 4, ∠ 5 & ∠ 3, ∠ 6 (Answer)

Step-by-step explanation:

1. See the attached figure to this answer.

2. Lines A and B are parallel to each other.

3. Line Z is the transversal.

4. The same side interior angles are ∠ 4, ∠ 6 & ∠ 3, ∠ 5.

5. The alternate interior angles are ∠ 3, ∠ 6 & ∠ 4, ∠5

6. Corresponding angles are ∠ 1, ∠ 6 & ∠ 2, ∠ 5 & ∠ 3, ∠ 7 & ∠ 4, ∠ 8.

7. Alternate interior angles are ∠ 4, ∠ 5 & ∠ 3, ∠ 6 (Answer)

7 0
3 years ago
Read 2 more answers
I NEED HELP AND IM ON A TIMED TEST
stira [4]

This Question is not Complete

Complete question

The number of absences per student in each of two classes is shown on the dot plots below.

A dot plot titled Number of absences per student in Misses Anderson's class. The number line goes from 0 to 6. There is 1 dot above 0, 3 above 1, 3 above 2, 3 above 3, 1 above 4, and 0 above 5 and 6.

A dot plot titled Number of absences per student in Misses Bergot's class. The number line goes from 0 to 6. There is 1 dot above 0, 1 above 1, 2 above 2, 3 above 3, 2 above 4, 1 above 5, and 1 above 6.

Which statements accurately compare the two data sets? Select three options.

a. The mean number of absences is greater in Mrs. Anderson’s class.

b. The mean number of absences is greater in Mrs. Bergot’s class.

c. There is more variability in Mrs. Anderson’s data set.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Answer:

b. The mean number of absences is greater in Mrs. Bergot’s class.

d. There is more variability in Mrs. Bergot’s data set.

e. The mean and MAD are better representations of these data sets than the median and IQR.

Step-by-step explanation:

From the above data given in the question and the options given to us, we can observe from the comparison of both the number of absences in Mrs Bergot's class to that in Mrs Anderson's class, there will be a presence of variation in the data of one of the classes and that class happens to be Mrs Bergot's class.

The appropriate statistical tool that we can be used to determine and measure the centre of variability of the data is Mean and Mean Absolute Deviation.

7 0
3 years ago
Given the following perfect square trinomial, fill in the missing term. (2 points)<br> 9x^2 +___+25
Zielflug [23.3K]

Answer:

30x

Step-by-step explanation:

missing must be 2×3x×5=30x

9x²+30x+25=(3x+5)²

5 0
3 years ago
Which best describe the relationship between the two lines describe below?
Anna007 [38]

we have

6x+3y=12 -----> line p

Find the slope

3y=-6x+12

y=-2x+4

m=-2

-4x=2y-2 -----> line Q

2y=-4x+2

y=-2x+1

m=-2

therefore

the lines are parallel because their slopes are equal

7 0
1 year ago
Carmen is a professor at a local university. In collecting data on her Introduction to Business course for a year, she wants to
AVprozaik [17]

Answer:

\boxed {\boxed {\sf z=2.2}}

Step-by-step explanation:

The z-score tells us how many standard deviations a value is away from the mean.

The formula is:

z=\frac{x- \overline{x}}{s}

where x is the value, \overline {x} is the mean, and s is the standard deviation.

We want to find the z-score for the score of an 83, the mean is 72, and the standard deviation is 5.

x=83 \\\overline {x}= 72 \\s=5

Substitute the values into the formula.

z=\frac{83-72}{5}

Solve the numerator.

z=\frac{11}{5}

Divide.

z=2.2

The z-score is 2.2, which means the score of 83 is 2.2 standard deviations above the mean.

3 0
3 years ago
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