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valentinak56 [21]
3 years ago
5

a family of 4 spend $104 for tickets to a concert all of the tickets were the same price what was the cost of each ticket?

Mathematics
2 answers:
wolverine [178]3 years ago
8 0
26 dollars is the amount
USPshnik [31]3 years ago
7 0
Hello There!

104 / 4 = 26
It was $26 per ticket.

Hope This Helps You!
Good Luck :) 

- Hannah ❤
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Rolls are being prepared to go to grocery stores. Divide 72 rolls into 2 groups so the ratio is 3 to 5. (please include your wor
natali 33 [55]
\sf 3:5 \to 3x:5x\\\\3x +5 = 8x\\ 8x = 72\\ x = 9\\\\9\times 3 =27\\9\times 5 =45\\ 27+45=72\\\\so~ the~ 2~ groups ~are~ 27~ and~ 45
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3 years ago
For the function defined by [Image Displayed], What is the constant of proportionality?
GaryK [48]

Answer:

I think the answer is undefined because the question above is an expression of f of x not a statement of variation which should have a constant of proportionality

3 0
3 years ago
Donatello Co. has identified an activity cost pool to which it has allocated estimated overhead of $9,600,000. It has determined
ahrayia [7]

Answer:

option (a) Widgets $2,400,000, Gadgets $1,800,000, Targets $5,400,000

Step-by-step explanation:

Data provided in the question:

Allocated estimated overhead = $9,600,000

Expected use of cost drivers for the activity = 800,000 inspections.

Inspections required by Widgets = 200,000

Inspections required by Gadgets = 150,000

Inspections required by Targets = 450,000

Therefore,

Total overhead per activity = \frac{\textup{estimated overhead}}{\textup{Total activity}}

= \frac{\textup{9,600,000}}{\textup{800,000 }}

= $12 per activity

Thus,

Overhead allocated to Widgets = 200,000 × 12 = $2,400,000

Overhead allocated to Gadgets = 150,000 × 12 = $1,800,000

Overhead allocated to Target = 450,000 × 12 = $5,400,000

Hence, The correct answer is option (a)

8 0
3 years ago
If the density of a 35.cm3 block of wood is .85 g./ml calculate the woods mass.
Reil [10]
So the equation you're going to be using is mass = density x volume 
So the volume of your block is 35cm^3, and your density is .85g/ml 

so your equation would be 

mass=.85g/ml x 35cm^3 

your final answer is 29.75g/cm^3

Hope this helps :) 
6 0
3 years ago
(Ross 5.15) If X is a normal random variable with parameters µ " 10 and σ 2 " 36, compute (a) PpX ą 5q (b) Pp4 ă X ă 16q (c) PpX
pochemuha

Answer:

(a) 0.7967

(b) 0.6826

(c) 0.3707

(d) 0.9525

(e) 0.1587

Step-by-step explanation:

The random variable <em>X</em> follows a Normal distribution with mean <em>μ</em> = 10 and  variance <em>σ</em>² = 36.

(a)

Compute the value of P (X > 5) as follows:

P(X>5)=P(\frac{x-\mu}{\sigma}>\frac{5-10}{\sqrt{36}})\\=P(Z>-0.833)\\=P(Z

Thus, the value of P (X > 5) is 0.7967.

(b)

Compute the value of P (4 < X < 16) as follows:

P(4

Thus, the value of P (4 < X < 16) is 0.6826.

(c)

Compute the value of P (X < 8) as follows:

P(X

Thus, the value of P (X < 8) is 0.3707.

(d)

Compute the value of P (X < 20) as follows:

P(X

Thus, the value of P (X < 20) is 0.9525.

(e)

Compute the value of P (X > 16) as follows:

P(X>16)=P(\frac{x-\mu}{\sigma}>\frac{16-10}{\sqrt{36}})\\=P(Z>1)\\=1-P(Z

Thus, the value of P (X > 16) is 0.1587.

**Use a <em>z</em>-table for the probabilities.

8 0
3 years ago
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