Answer:
x = 44/3 = mixed number - 14 2/3
Step-by-step explanation:
Divide using long division. The whole number portion will be the number of times the denominator of the original fraction divides evenly into the numerator of the original fraction, and the fraction portion of the mixed number will be the remainder of the original fraction division over the denominator of the original fraction.
A=andy's age
b=belinda's age
3a=11+2b
a+b=-2+2b
wowie
a+b=-2+2b
minus b from both sides
a=b-2
subsitute b-2 for a
3a=11+2b
3(b-2)=11+2b
3b-6=11+2b
minus 2b from both sides
b-6=11
add 6 to both sides
b=17
subsitute
a=b-2
a=17-2
a=15
andy is 15
belinda is 17
<h3>Answer: 41</h3>
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Work Shown:
See the diagram below.
A rectangle is cut along one of the diagonals to form two right triangles. Focus on just one of the triangles.
a = 9 and b = 40 are legs of the right triangle. The hypotenuse is some unknown value c.
Use the Pythagorean theorem to solve for c
a^2 + b^2 = c^2
9^2 + 40^2 = c^2
81 + 1600 = c^2
1681 = c^2
c^2 = 1681
c = sqrt(1681)
c = 41
The other diagonal is also 41 units long because every rectangle has both diagonals equal to one another.
Answer:
The answer is: (3x+4y)^2
Step-by-step explanation:
hope this helps :)
The problem is that ∃xp(x) is true, and <span>∃xq(x) is true means that for some x=x1, p(x) is true, and for some x=x2, q(x) is true. There is no guarantee that x1=x2, although it is not impossible.
However, </span><span>∃x(p(x) ∧ q(x)) means that for the same x=x0, p(x0) is true, and q(x0) is true. This cannot be implied from the first proposition, therefore
</span>
<span>∃xp(x) ∧ ∃xq(x) => ∃x(p(x) ∧ q(x)) is a false statement.</span>