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3 years ago

What is the answer to a(8+2b-6)

Mathematics

2 answers:

Westkost [7]3 years ago

7 0

2a +2ab

Hope this helps.

uranmaximum [27]3 years ago

7 0

The answer would be 2ab+2a

To distribute it’d look more like this: 8a+2ab-6a

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Which of the following are valid names for the given triangle? Check all that apply V ALOM BNLMZ C.PAMLZ DXZML WENZMO 72 FRAZMD

crimeas [40]

The answer is C.pamlz dxzml

8 0

3 years ago

Consider the following system of equations:

ASHA 777 [7]

A.

Cause the y and x you get from solving the system, is the intersection point :)
Written like this (x, y)

3 0

4 years ago

An exterior angle of a triangle is 124. And opposite interior angle is 72. Find all the angles of the triangle

Anna35 [415]

Answer:

The measure of all the three angles of the triangle are;

56°, 72° and 52°

Step-by-step explanation:

The given parameters are;

The measure of the exterior angle of the triangle = 124°

The measure of one of the opposite interior angle = 72°

Therefore, we have;

The measure of the interior angle adjacent to the exterior triangle = 180° - 124° = 56° (Sum of angles on a straight line)

From the sum of the interior angles in a triangle = 180°, we have;

The measure of the third interior angle of the triangle = 180° - 56° - 72° = 52°

Therefore, the measure of all the three angles of the triangle are;

56°, 72° and 52°.

5 0

3 years ago

Draw a array to show how arrange 20 chairs into 5 equal rows

DedPeter [7]

There would be 4 chairs in each row

5 0

3 years ago

If c is the line segment connecting (x1,y1) to (x2,y2), show that the line integral of xdy-ydx=x1y2-x2y1......this is in a chapt

MatroZZZ [7]

Green's theorem doesn't really apply here. GT relates the line integral over some *closed* connected contour that bounds some region (like a circular path that serves as the boundary to a disk). A line segment doesn't form a region since it's completely one-dimensional.

At any rate, we can still compute the line integral just fine. It's just that GT is irrelevant.

We parameterize the line segment by

$\mathbf r(t)=\langle x_1,y_1\rangle(1-t)+\langle x_2,y_2\rangle t$
$\implies\mathbf r(t)=\langle x_1+(x_2-x_1)t,y_1+(y_2-y_1)t\rangle$

with $0\le t\le1$ . Then we find the differential:

$\mathbf r(t)\equiv\langle x,y\rangle=\langle x_1+(x_2-x_1)t,y_1+(y_2-y_1)t\rangle$
$\implies\mathrm d\mathbf r\equiv\langle\mathrm dx,\mathrm dy\rangle=\langle x_2-x_1,y_2-y_1\rangle\,\mathrm dt$

with $0\le t\le1$ .

Here, the line integral is

$\displaystyle\int_{\mathcal C}x\,\mathrm dy-y\,\mathrm dx=\int_{\mathcal C}\langle-y,x\rangle\cdot\langle\mathrm dx,\mathrm dy\rangle$
$=\displaystyle\int_{t=0}^{t=1}\langle-y_1-(y_2-y_1)t,x_1+(x_2-x_1)t\rangle\cdot\langle x_2-x_1,y_2-y_1\rangle\,\mathrm dt$
$=\displaystyle\int_{t=0}^{t=1}(x_1y_2-x_2y_1)\,\mathrm dt$
$=(x_1y_2-x_2y_1)\displaystyle\int_{t=0}^{t=1}\,\mathrm dt$
$=x_1y_2-x_2y_1$

as required.

4 0

4 years ago