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viktelen [127]
2 years ago
14

Which of the following are valid names for the given triangle? Check all that apply V ALOM BNLMZ C.PAMLZ DXZML WENZMO 72 FRAZMD​

Mathematics
1 answer:
crimeas [40]2 years ago
8 0
The answer is C.pamlz dxzml
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What is an algebraic expression to represent the perimeter of a rectangle with a width of x+5 and a length of 3x+10?
Sveta_85 [38]
We know that the area of a rectangle is equal to the width multiplied by the length. So in this case the algebraic expression is (x+5)*(3x+10). You get 3x^2 +10x +15x +50= 3x^2 +25x +50.
5 0
2 years ago
A cylinder has a volume of 3201 cubic inches and a height of 5 inches.
enot [183]

Answer:

r≈14.28in

h Height

5

in

V Volume

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Using the formula

V=πr2h

Solving forr

r=V

πh=3201

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5 0
2 years ago
Solve the equation |4m| − 5 = 11.
Leno4ka [110]

Answer:

Please refer to the attachment

6 0
2 years ago
The eleventh term from the end of the AP 14, 19, 24, …………., 264 is
vazorg [7]

Answer:

<h2>The eleventh term of the sequence is 64</h2>

Step-by-step explanation:

The sequence given is an arithmetic sequence

14, 19, 24, …………., 264

The nth term of an arithmetic sequence is given as;

Tn = a+(n-1)d where;

a is the first term = 14

d is the common difference = 19-14=24-19 = 5

n is the number of terms = 11(since we are to look for the eleventh term of the sequence)

substituting the given values in the formula given;

T11 = 14+(11-1)*5

T11 = 14+10(5)

T11 = 14+50

T11 = 64

The eleventh term of the sequence is 64

6 0
3 years ago
How do I find this help please
KIM [24]
Area of the sector = 1/2 * r^2 * theta where theta is the angle subtended by the arc at the center  ( in radians)

In this case m < theta = 360 - 235 = 125 degrees or  2.182 radians

So, the area of shaded area = 1/2 * 20^2 * 2.182 =   436.4 in^2
8 0
3 years ago
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