Thus L.H.S = R.H.S that is 2/√3cosx + sinx = sec(Π/6-x) is proved
We have to prove that
2/√3cosx + sinx = sec(Π/6-x)
To prove this we will solve the right-hand side of the equation which is
R.H.S = sec(Π/6-x)
= 1/cos(Π/6-x)
[As secƟ = 1/cosƟ)
= 1/[cos Π/6cosx + sin Π/6sinx]
[As cos (X-Y) = cosXcosY + sinXsinY , which is a trigonometry identity where X = Π/6 and Y = x]
= 1/[√3/2cosx + 1/2sinx]
= 1/(√3cosx + sinx]/2
= 2/√3cosx + sinx
R.H.S = L.H.S
Hence 2/√3cosx + sinx = sec(Π/6-x) is proved
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Answer:
1200
Step-by-step explanation:
3/4 of 200 = 150
150 is 1/8 of 1200
Step-by-step explanation:
here u go.
hope it helps you
Answer:
An airplane cruises 1 kilometer in 1/12 of a minute. What is its cruising speed?<u>200</u>
Given:
The parent function is:
The other function is:
To find:
The statement that describes a key feature of function g.
Solution:
We have,
Using these two functions, we get
Putting 
, we get
The y-intercept of the function g at (0,2). So, option A is correct and option B is incorrect.
We know that 
as 
and it will never intersect the line 
. It means the horizontal asymptote of the function g is
Therefore, the correct option is A.
