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Finger [1]
3 years ago
13

There are 24 books on the bookcase 3/4 of these books are science fiction how many books are science fiction

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
7 0

Answer:

<u>18 of the books are science fiction.</u>

Step-by-step explanation:

24/4 = 6

Science fiction - 6+6+6 = 18

Not science fiction - 24 - 18 = 6

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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You buy a game for $40, and the sales tax is $2. What percent of the game price are you paying in sales tax? Your doctor told yo
AfilCa [17]

Answer:

a) 5%

b) 24%

Step-by-step explanation:

a) You buy a game for $40, and the sales tax is $2. What percent of the game price are you paying in sales tax?

Percentage you are paying in sales tax

= Sales tax / Sale price of the game × 100

= $2/$40 × 100

= 5%

b) Your doctor told you to eat 25 grams of fiber each day. You had 6 grams of fiber for breakfast. What percent of the 25 grams of fiber have you eaten so far?

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3 0
3 years ago
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo
muminat

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: {\displaystyle P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}}

Where \lambda is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}

Substitute the respective values in the above formula.

P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})

P(k > 2)= 1 - (0.44596)

P(k > 2)=0.55404

Hence, the required probability is 0.55404.

4 0
3 years ago
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