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Katena32 [7]
3 years ago
13

Which of the following is a solution to the second order differential equation LaTeX: y''=-4y y ″ = − 4 y ? To answer this quest

ion, attempt to verify each of the following proposed solutions. a. LaTeX: y=\sin2t y = sin ⁡ 2 t b. LaTeX: y=-\frac{2}{3}t^3 y = − 2 3 t 3 c. LaTeX: y=\cos2t y = cos ⁡ 2 t d. LaTeX: y=e^{2t} y = e 2 t e. LaTeX: y=\frac{y''}{-4}

Mathematics
1 answer:
Paraphin [41]3 years ago
5 0

Answer:

  • y = sin(2t)
  • y = cos(2t)

Step-by-step explanation:

In the case of each of the answers listed above, the second derivative is equal to -4 times the function, as required by the differential equation.

For y = 2/3t^3, the second derivative is 4t, not -4y.

For y = e^(2t), the second derivative is 4y, not -4y.

__

The graph shows the sum of the second derivative and 4y is zero for the answers indicated above, and not zero for the other two proposed answers.

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what is the common ratio for the geometric sequence below, written as a fraction? 768, 480, 300, 187.5, …
Crazy boy [7]

Let

a1=768\\a2=480\\a3=300\\a4=187.5

Step 1

Find \frac{a2}{a1}

\frac{a2}{a1} =\frac{480}{768}

Divide by 96 numerator and denominator

\frac{480}{768} =\frac{\frac{480}{96}}{\frac{768}{96}} \\   \\ \frac{480}{768}=\frac{5}{8}

a2=a1*\frac{5}{8}

Step 2

Find \frac{a3}{a2}

\frac{a3}{a2} =\frac{300}{480}

Divide by 60 numerator and denominator

\frac{300}{480} =\frac{\frac{300}{60}}{\frac{480}{60}} \\   \\  \frac{300}{480}=\frac{5}{8}

a3=a2*\frac{5}{8}

Step 3

Find \frac{a4}{a3}

a4=187.5 \\ a4=187\frac{1}{2} \\ \\ a4=\frac{375}{2}

\frac{a4}{a3} =\frac{\frac{375}{2}}{300}  \\ \\  \frac{a4}{a3} =\frac{375}{600}

Divide by 75 numerator and denominator

\frac{375}{600} =\frac{\frac{375}{75}}{\frac{600}{75}} \\   \\ \frac{375}{600}=\frac{5}{8}

a4=a3*\frac{5}{8}

In this problem

The geometric sequence formula is equal to

a(n+1)=a(n)*\frac{5}{8}\\

For n\geq 1

therefore

the answer is

the common ratio for the geometric sequence above is \frac{5}{8}



6 0
3 years ago
Read 2 more answers
Can someone pls help me with this.. Thanks in advance
vfiekz [6]
3,6,8,5, these are your answers
5 0
3 years ago
Read 2 more answers
Currently, in Littlefield, jobs arrive at 12 per day and you have (just) enough capacity at each station (i.e., the departure ra
OlgaM077 [116]

Answer:

The WIP limit is 0.50 days.

Step-by-step explanation:

The Computation of WIP limits:

to begin with, it is required to compute the process and procedure efficiency which will be computed as follows:

Value Added Time = 12 days (arriving time)

Non-Value-Added Time = 12 days (departure time)

Efficiency = Value Added / (Value Added + Non-Value Added)

                = 12 / (12+12)

                = 12 / 24

               = 0.50 or 50%

the most obligatory throughput time will be 0.25 days to realize the profits

WIP limit = Throughput time / Efficiency  

               = 0.25 / 50%

               = 0.50 days.

The WIP limit is 0.50 days.

6 0
3 years ago
What is 5 to the power of 6 over 5 to the power of 2
AlekseyPX

Answer:

625

Step-by-step explanation: 5^6/5^2

multiply 5^6 and than devide your answer with 5^2

6 0
2 years ago
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4n+12=4 What does n equal?
solong [7]

Answer:

n = -2

Step-by-step explanation:

4n + 12 = 4

Subtract 12 from both sides.

4n = -8

Divide both sides by 4.

n = -2

3 0
3 years ago
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