The polynomial is not factorable, so use the quadratic formula.
y^2 + 8y + 19 = 0
x = (-b +- sqrt(b^2 - 4ac))/(2a)
x = (-8 +- sqrt(8^2 - 4(1)(19))/(2 * 1)
x = (-8 +- sqrt(64 - 76))/2
x = (-8 +- sqrt(-12))/2
If you have not learned imaginary/complex numbers, then the answer is "No solution" since there is no real number solution.
If you have learned imaginary/complex numbers, then we'll continue.
x = (-8 +- 2i sqrt(3))/2
x = -4 +- i sqrt(3)
Answer:
<em>Graph below</em>
Step-by-step explanation:
<u>Transformations</u>
Triangle ABC has coordinates A=(-4,2) B=(-2,6) C=(3,2)
We'll use the transformation (x,y) -> (2x, y+3) to map it to the triangle A'B'C'. Let's calculate the coordinates:
A'=(-8,5)
B'=(-4,9)
C'=(6,5)
The image below shows both triangles in the same grid
Answer: (1, 2) (The third option)
Step-by-step explanation: A solution has to be on the line. (1, 2) is the only point that isn't on the line.