Which of the following is a solution to the second order differential equation LaTeX: y''=-4y y ″ = − 4 y ? To answer this quest
ion, attempt to verify each of the following proposed solutions. a. LaTeX: y=\sin2t y = sin 2 t b. LaTeX: y=-\frac{2}{3}t^3 y = − 2 3 t 3 c. LaTeX: y=\cos2t y = cos 2 t d. LaTeX: y=e^{2t} y = e 2 t e. LaTeX: y=\frac{y''}{-4}
1 answer:
Answer:
- y = sin(2t)
- y = cos(2t)
Step-by-step explanation:
In the case of each of the answers listed above, the second derivative is equal to -4 times the function, as required by the differential equation.
For y = 2/3t^3, the second derivative is 4t, not -4y.
For y = e^(2t), the second derivative is 4y, not -4y.
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The graph shows the sum of the second derivative and 4y is zero for the answers indicated above, and not zero for the other two proposed answers.
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The linear equation in slope intercept form for population of Jose's town is y = 320x + 2400.
<u>Solution:</u>
Given, the population of Jose's town in 1995 was 2400 and the population in 2000 was 4000,
Let x represent the number of years since 1995.
We have to write a linear equation, in slope- intercept form, that represents this data.
Now, let the change in population per year be p.
Then, population in a year = population change per year number of years + population in 1995.
⇒population in a year = p x + population in 1995
⇒ population in a year = p x + 2400
Here we have an case that, population in 2000 is 4000
Then, number of years since 1995 = 5
So, 4000 = p 5 + 2400 ⇒ 5p = 4000 – 2400 ⇒ 5p = 1600 ⇒ p = 320
Then, our equation will be population in a year = 320x + 2400
Considering the population in a year as y ⇒ y = 320x + 2400.
Hence, the linear equation in slope intercept form is y = 320x + 2400.
The equation of a parabola with a directrix at y = -3 and a focus at (5 , 3) is y = one twelfth (x - 5)² ⇒ 1st answer
Step-by-step explanation:
The form of the equation of the parabola is (x - h)² = 4p(y - k), where
- The vertex of the parabola is (h , k)
- The focus is (h , k + p)
- The directrix is at y = k - p
∵ The focus of the parabola is at (5 , 3)
- Compare it with the 2nd rule above
∴ h = 5
∴ k + p = 3 ⇒ (1)
∵ The directrix is at y = -3
- By using the 3rd rule above
∴ k - p = -3 ⇒ (2)
Solve the system of equations to find k and p
Add equations (1) and (2) to eliminate p
∴ 2k = 0
- Divide both sides by 2
∴ k = 0
- Substitute the value of k in equation (1) to find p
∵ 0 + p = 3
∴ p = 3
Substitute the values of h , k , and p in the form of the equation above
∵ (x - 5)² = 4(3)(y - 0)
∴ (x - 5)² = 12 y
- Divide both sides by 12
∴ (x - 5)² = y
- Switch the two sides
∴ y = (x - 5)²
The equation of a parabola with a directrix at y = -3 and a focus at (5 , 3) is y = (x - 5)²
Learn more:
you can learn more about the quadratic equations in brainly.com/question/8054589
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