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Rina8888 [55]
2 years ago
15

Simplify (2-7i)+(3+9i) step by step

Mathematics
2 answers:
Mariana [72]2 years ago
5 0

Answer:

first identify the like terms;

(2-7i)+(3+9i)

(2+3-7i+9i)

5+2i

gayaneshka [121]2 years ago
3 0

Answer:

5 + 2i

Step-by-step explanation:

1) Remove parentheses

2 - 7i + 3 + 9i

2) Collect like terms

(2 + 3) + (-7i + 9i)

3) Simplify

5 + 2i

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82nd term = -103
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What is the simplest form of the radical expression 8?
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Find the value of g(5).<br><br> g(x) = (x – 3)(x + 1)
liberstina [14]

Answer:

Step-by-step explanation:

Exponential functions have a horizontal asymptote. The equation of the horizontal asymptote is

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Horizontal Asymptote:

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8 0
3 years ago
A raffle offers one $8000.00 prize, one $4000.00 prize, and five $1600.00 prizes. There are 5000 tickets sold at $5 each. Find t
Harman [31]

Answer:

The expectation is  E(1 )= -\$ 1

Step-by-step explanation:

From the question we are told that  

     The first offer is  x_1 =  \$ 8000

     The second offer is  x_2 =  \$ 4000

      The third offer is  \$ 1600

      The number of tickets is  n  =  5000

      The  price of each ticket is  p= \$ 5

Generally expectation is mathematically represented as

             E(x)=\sum  x *  P(X = x )

     P(X =  x_1  ) =  \frac{1}{5000}    given that they just offer one

    P(X =  x_1  ) = 0.0002    

 Now  

     P(X =  x_2  ) =  \frac{1}{5000}    given that they just offer one

     P(X =  x_2  ) = 0.0002    

 Now  

      P(X =  x_3  ) =  \frac{5}{5000}    given that they offer five

       P(X =  x_3  ) = 0.001

Hence the  expectation is evaluated as

       E(x)=8000 *  0.0002 + 4000 *  0.0002 + 1600 * 0.001

      E(x)=\$ 4

Now given that the price for a ticket is  \$ 5

The actual expectation when price of ticket has been removed is

      E(1 )= 4- 5

      E(1 )= -\$ 1

4 0
3 years ago
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