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3 years ago

What is the missing side

Mathematics

1 answer:

igomit [66]3 years ago

8 0

X = 5 inches the answer is

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Write an expression for 5 times the difference of twice a number and 4

777dan777 [17]

Answer:

1. 50-x

2. 2x+189

3. x+109

4. x+99

5. x*(76-39)

6. 75+x

7. 45-3x

8. 2x+15

9. 3x-25

10. x*(x+88)

Step-by-step explanation:

4 0

2 years ago

N is the set of odd natural numbers greater than 11 and less than 21. Use set notation to write the elements of N. N

S_A_V [24]

Answer:

N = {13, 15, 17, 19}

Step-by-step explanation:

The natural numbers greater than 11 and less than 21 are:

12, 13, 14, 15, 16, 17, 18, 19 and 20

Odd numbers are numbers that have remainders when divided by 2. Out of the numbers above, the numbers with remainders when divided by 2 are 13, 15, 17 and 19.

Since N is the set of odd natural numbers greater than 11 and less than 21,

N = {13, 15, 17, 19}

4 0

3 years ago

Read 2 more answers

What is the 11th term of the sequence: 7, 13, 19, 25, ....

wel

pattern is adding 6

so the 11th would be 67

8 0

3 years ago

Read 2 more answers

Over the summer, for every 14 okra seeds Dana planted, 9 grew into plants. If he planted 210 okra seeds, how many grew into plan

Katena32 [7]

210s(9p/14s)=135p

So 135 seeds grew into plants.

8 0

3 years ago

Read 2 more answers

3^x= 3*2^x solve this equation

kompoz [17]

In the equation

$3^x = 3\cdot 2^x$

divide both sides by $2^x$ to get

$\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3$

Take the base-3/2 logarithm of both sides:

$\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}$

Alternatively, you can divide both sides by $3^x$ :

$\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13$

Then take the base-2/3 logarith of both sides to get

$\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}$

(Both answers are equivalent)

8 0

2 years ago