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Georgia [21]
3 years ago
7

The total budget for a landscaping project was $349.02, and the project called for 42 plants. What is the average cost per plant

? Explain the method used for solving the problem.
Mathematics
1 answer:
Marianna [84]3 years ago
8 0

Answer:

349.02 / 42 = answer

Step-by-step explanation:

method used is dividing total cost by number of goods used gives the exact cost of each plant

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Lynn asked six friends how many cars their parents own. She recorded 1, 1, 2, 2, 2, and 4 cars.
Paladinen [302]

Answer:

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Step-by-step explanation:

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3 years ago
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You need to rent a moving truck for a day you have identify two companies to rent trucks company a charges $45 per day plus $.10
goldfiish [28.3K]
I believe the answer is 150 miles, with a cost of $60
6 0
3 years ago
Between which two consecutive integers does <img src="https://tex.z-dn.net/?f=%5Csqrt%7B%7D%2012%5C%5C" id="TexFormula1" title="
Annette [7]

The most appropriate choice for square root will be given by-

\sqrt{12} lies between 3 and 4

What is square root of a number?

Number raised to the power \frac{1}{2} is the square root of  the number.

Here

\sqrt{12}\\ 2\sqrt{3}\\ 2*1.732\\3.464\\

3.464 lies between 3 and 4

\sqrt{12} lies between 3 and 4

To learn more about square root of a number, refer to the link:

brainly.com/question/3617398

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7 0
1 year ago
13. A catapult launches a boulder wint an upward velocity of 122 feet per second the height of the boulder (h) in feet after t s
SashulF [63]
For this case we have the following expression:
 h (t) = - 16t ^ 2 + 122t + 10
 We look for the maximum of the function, for this, we derive:
 h '(t) = - 32t + 122
 We match zero:
 -32t + 122 = 0
 We cleared t:
 t = 122/32
 t = 3.8125 s
 Then, the maximum height will be:
 h (3.8125) = - 16 * (3.2185) ^ 2 + 122 * (3.2185) +10
 h (3.8125) = 236.92 feet
 Answer:
 
It takes the boulder to reach maximum height about:
 
t = 3.8125 s
 
the boulders maximum height is:
 
236.92 feet
3 0
3 years ago
Simplify each only using positive exponents:<br> 2x^-3 • 4x^2<br> 2x^4 • 4x^-3<br> 2x^3y^-3 • 2x
erica [24]
<h2>Answer:</h2>

\frac{2}{x}

\frac{x}{2}

\frac{4x^4}{y^3}

<h2>Step-by-step explanation:</h2>

a. 2x^-3 • 4x^2

To solve this using only positive exponents, follow these steps:

i. Rewrite the expression in a clearer form

2x⁻³ . 4x²

ii. The position of the term with negative exponent is changed from denominator to numerator or numerator to denominator depending on its initial position. If it is at the numerator, it is moved to the denominator. If otherwise it is at the denominator, it is moved to the numerator. When this is done, the negative exponent is changed to positive.

In our case, the first term has a negative exponent and it is at the numerator. We therefore move it to the denominator and change the negative exponent to  positive as follows;

\frac{1}{2x^3} . 4x^2

iii. We then solve the result as follows;

\frac{1}{2x^3} . 4x^2 = \frac{2}{x}

Therefore, 2x⁻³ . 4x² = \frac{2}{x}

b. 2x^4 • 4x^-3

i. Rewrite as follows;

2x⁴ . 4x⁻³

ii. The second term has a negative exponent, therefore swap its position and change the negative exponent to a positive one.

2x^4 . \frac{1}{4x^3}

iii. Now solve by cancelling out common terms in the numerator and denominator. So we have;

\frac{x}{2}

Therefore, 2x⁴ . 4x⁻³ = \frac{x}{2}

c. 2x^3y^-3 • 2x

i. Rewrite as follows;

2x³y⁻³ . 2x

ii. Change position of terms with negative exponents;

2x^3.\frac{1}{y^3} .2x

iii. Now solve;

\frac{4x^4}{y^3}

Therefore, 2x³y⁻³ . 2x = \frac{4x^4}{y^3}

8 0
3 years ago
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