Answer:
hai
like you see, there are 2 line on the triangle.
68° is looking in front of one line, so the other line's front have to be 68°
now we found 2 corner of triangle.
a triangle's sum of interior angles equal to 180°
68°+68° = 136°.
now i have to remove 136 from 180 to find our x
180°-136° = 44°
x = 44°
good luck(:
This is not possible because arcsin is the angle that will give you a sine value of 2. Sine values range from -1 to 1; there is no angle that will give you a sine of 2.
Here is the formula you'll need
Total = Principal * (1 + (rate/n))^n*years
I don't know how to solve that for "n" so we'll use trial and error.
If compounded annually, total =
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<span>
<span>
10,841.24
</span>
</span>
</span>
If compounded quarterly, total =
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<span>
<span>
10,955.64
</span>
</span></span><span>If compounded monthly, total =
</span>
<span>
<span>
<span>
10,981.82
</span>
</span>
</span>
If compounded daily, total =
<span>
<span>
<span>
10,994.58
</span>
</span>
</span>
Therefore the answer is "A", daily.
Source:
http://www.1728.org/compint3.htm
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</span>
From Sweatcoin, London to the residence of Santa Claus is about 4,280 km away.
<h3>Where is the Santa Clause's residence?
</h3>
The residence of Santa Clause is popularly known as the North Pole.
According to the above, we have to roughly calculate the distance from Sweatcoin in London to the North Pole. This distance is equivalent to about 4,280 km
Learn more about London in: brainly.com/question/7416097
QUESTION:
A battery was charged. When the charging began, it was 23 percent full. After 30 minutes of charging, the battery was 89 percent full. how fast did the battery charge and how long did it take?
Solution :
<u>Given</u>
- Initial amount of charge = 23%
- Amount after charge = 89%
<u>procedu</u><u>re</u>
Let the rate of charging be r .
r = (change in charge level) / (time interval) = (89% - 23%) / (30 min) = 2.2 % per minute
charge = (rate of charging)(time) + (initial charge)
100% = r*t + 23%
100% = (2.2 %/min)t + 23%
Solve for t and get
t = [(100 - 23) / 2.2]
Answer = 35 min