All categories

3 years ago

What do you do with fractions in finding absolute value

Mathematics

1 answer:

Furkat [3]3 years ago

4 0

Absolute value only removes the negative signs. Just multiply the numerator and the denominator

You might be interested in

Simplify each expression by using the Distributive Property and combine like terms to simplify the expression.-2(-x-1)-(x+9)

Ymorist [56]

-2(-x-1)-(x+9)

= -2x + 2 - x - 9

Rearrange

= -2x - x + 2 - 9

= -3x - 7

8 0

9 months ago

NEED HELP ASAP PLEASE PLEASE PLEASE

nignag [31]

Answer:

tanθ=1.17

Step-by-step explanation:

please see the attachment below

8 0

2 years ago

Substitute: 7.5x = 5.5x + 10

Umnica [9.8K]

The value of x is 5

<h3>What are algebraic expressions?</h3>

Algebraic expressions are expressions made up;

Factors
variables
terms
constants

They also consist of mathematical operations such as addition, multiplication, division, subtraction, parenthesis, brackets, etc

We have the expression as;

7.5x = 5.5x + 10

collect like terms

7.5x - 5.5x = 10

subtract the like terms

2.0x = 10

Make 'x' the subject

x = 10/2. 0

x = 5

Thus, the value of x is 5

Learn more about algebraic expressions here:

brainly.com/question/4344214

#SPJ1

7 0

1 year ago

HELP PLEASE!!! Thanks!

Irina18 [472]

Answer:

2) $\frac{\sqrt{77}}{11}$

3) 5√2

Step-by-step explanation:

Simplest radical form of an expression is the expression in radical so that there are no more square roots, cube roots, 4th roots, etc left to find, after rationalising the denominator ( if needed ).

2. Here the given expressions,

$\frac{\sqrt{7}}{\sqrt{11}}$

For rationalising the denominator multiply both numerator and denominator by √11,

$\frac{\sqrt{77}}{11}$

3. given expression,

$\sqrt{50}$

$=\sqrt{25\times 2}$

$=\sqrt{25}\times \sqrt{2}$ $(\because \sqrt{ab}=\sqrt{a}\sqrt{b})$

$=5\sqrt{2}$

8 0

2 years ago

Find the sum of each series, if it exists<br>91 + 85 + 79 + … + (29)

Natali [406]

Answer:

651.

Step-by-step explanation:

Note: In the given series it should be -29 instead of 29 because 29 cannot be a term of AP whose first term is 91 and common difference is -6.

Consider the given series is

$91+85+79+...+(-29)$

It is the sum of an AP. Here,

First term = 91

Common difference = 85 - 91 = -6

Last term = -29

nth term of an AP is

$a_n=a+(n-1)d$

where, a is first term and d is common difference.

$-29=91+(n-1)(-6)$

$-29-91=(n-1)(-6)$

$\dfrac{-120}{-6}=(n-1)$

$20=(n-1)$

$n=20+1=21$

Sum of AP is

$Sum=\dfrac{n}{2}[\text{First term + Last term}]$

$Sum=\dfrac{21}{2}[91+(-29)]$

$Sum=\dfrac{21}{2}[62]$

$Sum=651$

Therefore, the sum of given series is 651.

5 0

2 years ago