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podryga [215]
3 years ago
13

What do you do with fractions in finding absolute value

Mathematics
1 answer:
Furkat [3]3 years ago
4 0
Absolute value only removes the negative signs. Just multiply the numerator and the denominator


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Kristin goes to the mall and buys a pair of brand name sunglasses on sale
Free_Kalibri [48]

Answer:

$79.20 savings.

8 0
3 years ago
A newborn baby has 26,000,000,000 cells. An adult has about 1.9×10³ times as many as a newborn. About how many cells does an adu
Alenkinab [10]
*Hint* the ^ just means that the following numbers are powers like 1.9x10^3 is same as 1.9x10³


To figure this out just multiply 

26000000000 × 1.9x10³ = 4.94x10¹³ cells in adults
6 0
3 years ago
Lee Middle School orders 15 textbooks for every 12 students. The table shows how many textbooks the school orders for certain nu
Mariulka [41]

Answer: 90 textbooks


Step-by-step explanation:

everytime you multiply the number of students you multiply the books by the same number. to find how many times 72 was multiplied you divide it by 12.

72 ÷ 12 = 6

then multiply the original number of books (15) by 6.

15 * 6 = 90

so for every 72 students the school orders 90 textbooks

5 0
3 years ago
A friend is in 5th grade math and asks you to explain exponents with example. What do you say?
Vesnalui [34]

Answer:

If my friend is in 5th grade and they need an example on exponents I would show them something like this 7 to the 3 power would be equal to 7 times 7 times 7 which also equals 343 or 4 to the 4th power would be equal to 4 times 4 times 4 times 4 which equals 256

Step-by-step explanation:

This is a simpiler way to show a younger student how to figure out exponents also. Have a great day :D  

If you need help me and my older brother both share this account.

4 0
3 years ago
Can someone solve and explain this question plz​
oee [108]

firstly let's convert the mixed fraction to improper fraction, then hmmm let's see we have two denominators, 5 and 3, and their LCD will simply be 15, so we'll multiply both sides by that LCD to do away with the denominators, let's proceed,

\bf \stackrel{mixed}{2\frac{1}{3}}\implies \cfrac{2\cdot 3+1}{3}\implies \stackrel{improper}{\cfrac{7}{3}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{z}{5}-4=\cfrac{7}{3}\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{15}}{15\left( \cfrac{z}{5}-4 \right)=15\left( \cfrac{7}{3} \right)}\implies 3z-60=35 \\\\\\ 3z=95\implies z=\cfrac{95}{3}\implies z = 31\frac{2}{3}

4 0
3 years ago
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