Answer:
Explanation:
Blood group AB has both A and B antigens, but no antibodies. Blood group B has B antigens with anti-A antibodies in the plasma. Blood group A has A antigens on the red blood cells with anti-B antibodies in the plasma
Answer:
KE = 1/2mv squared (im not sure how to write the squared on top of the V but just add it there)
m=8 kg
Explanation:
Solve for m, plug in v = m/s and KE = 100J. The answer is m=8kg
The method of virus transmission which results in a greater spread of disease is through airborne transmission
The term 2pq represented in the hardy-weinberg equation is the frequency of heterozygotes and is denoted as option D.
<h3>What is Hardy-weinberg equation?</h3>
This mathematical equation is used to calculate the genetic variation of a population at equilibrium and can be seen below:
p² + 2pq + q² = 1
where
p² is dominant homozygous frequency (AA)
2pq is heterozygous frequency (Aa)
q² is recessive homozygous frequency (aa).
The 2pq can be seen as the heterozygous frequency which is therefore the reason why option D which is frequency of heterozygotes was chosen as the most appropriate choice.
Read more about Hardy-weinberg equation here brainly.com/question/5028378
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