5/54 or approximately 0.092592593
There are 6^3 = 216 possible outcomes of rolling these 3 dice. Let's count the number of possible rolls that meet the criteria b < y < r, manually.
r = 1 or 2 is obviously impossible. So let's look at r = 3 through 6.
r = 3, y = 2, b = 1 is the only possibility for r=3. So n = 1
r = 4, y = 3, b = {1,2}, so n = 1 + 2 = 3
r = 4, y = 2, b = 1, so n = 3 + 1 = 4
r = 5, y = 4, b = {1,2,3}, so n = 4 + 3 = 7
r = 5, y = 3, b = {1,2}, so n = 7 + 2 = 9
r = 5, y = 2, b = 1, so n = 9 + 1 = 10
And I see a pattern, for the most restrictive r, there is 1 possibility. For the next most restrictive, there's 2+1 = 3 possibilities. Then the next one is 3+2+1
= 6 possibilities. So for r = 6, there should be 4+3+2+1 = 10 possibilities.
Let's see
r = 6, y = 5, b = {4,3,2,1}, so n = 10 + 4 = 14
r = 6, y = 4, b = {3,2,1}, so n = 14 + 3 = 17
r = 6, y = 3, b = {2,1}, so n = 17 + 2 = 19
r = 6, y = 2, b = 1, so n = 19 + 1 = 20
And the pattern holds. So there are 20 possible rolls that meet the desired criteria out of 216 possible rolls. So 20/216 = 5/54.
Answer:
x-60
Step-by-step explanation:
You have to factor out the quadratic.
You know that one of the factors is x-40.
To factor:
Find a number that when added to -40, gives you -100, and also when multiplied, gives you 2400.
That such number is -60.
Add an x before it, and you get (x-60)
Answer:
1st ∡ = 15.5°
2nd ∡ = 77.25°
3rd ∡ = 87.25°
Step-by-step explanation:
1st ∡: x
2nd ∡: y
3rd ∡: z
Equations we can create from data given in problem:
y + z = 5x
z = 5x + 10
We have enough expressions to create an equation:
x + 5x + 5x + 10 = 180
11x = 170
x = 15.5
y = 5(15.5) = 77.25
z = y + 10 = 87.25
The total area of the stable is 20,250 sq. ft.
Let n = total number of box stalls.
Each box stall is a square of length 9 ft.
Total area = 9^2n = 81n ft².
Therefore
81n = 20250
n = 20250/81 = 250
Answer: 250 horses.
