Multiplication with exponents confuses me..

Q # 19. I need your help on this

Komok [63]

Solution:

we have been asked to find a function for the given sitatution

The given situation is

A movie store sells DVDs for $11 each. what is the cost C of n DVDs.

Cost of 1 DVD is $11, then the cost of 2 DVDS will be 2x11=$22.

Cost of 1 DVD is $11, then the cost of 3 DVDS will be 3x11=$33.

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Cost of 1 DVD is $11, then the cost of n DVDS will be nx11=$11n.

Since the price is increasing exactly by $11 for each additional DVDS so the Graph will be discrete.

Hence the correct option is C=11n, Discrete.

7 0

4 years ago

Describe the 2 transformations that occur when the graph of f(x) =x −−√ is transformed to the graph of g(x) = 2x√ +3 .

Flauer [41]

Answer:

Dilation followed by Translation.

Step-by-step explanation:

We have the function $f(x)=\sqrt{x}$ .

The new transformed function is $g(x)=2\sqrt{x}+3$

Now, the transformation applied to f(x) to obtain g(x) are:

1. Dilation - it is the transformation that changes the size/shape of the figure. It is generally of the form kf(x) where k is constant.

Since, we are dilating the given function by 2 units, the new dilated function becomes $2\sqrt{x}$ .

2. Translation - it is the transformation that shifts the figure in any direction. When the function is shifted vertically, the general form becomes f(x)+k.

As, we see that the new dilated function is shifted 3 units upwards, the final translated function becomes $g(x)=2\sqrt{x}+3$ .

Hence, the transformations applied to obtain g(x) from f(x) are Dilation followed by Translation.

5 0

3 years ago

You invested $ 7000 between two accounts paying 3 % and 5 % annual? interest, respectively. If the total interest earned for the

natita [175]

Answer:

In the first account was invested $\$3,000$ at 3%

In the second account was invested $\$4,000$ at 5%

Step-by-step explanation:

we know that

The simple interest formula is equal to

$I=P(rt)$

where

I is the Interest Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

First account

$t=1 years\\ P=\$x\\ r=0.03$

substitute in the formula above

$I=x(0.03*1)$

$I=0.03x$

Second account

$t=1 years\\ P=\$(7,000-x)\\ r=0.05$

substitute in the formula above

$I=(7,000-x)(0.05*1)$

$I=350-0.05x$

Remember that

The interest is equal to $\$290$

so

Adds the interest of both accounts

$0.03x+350-0.05x=\$290$

$0.05x-0.03x=350-290$

$0.02x=60$

$x=\$3,000$

therefore

In the first account was invested $\$3,000$ at 3%

In the second account was invested $\$7,000-\$3,000=\$4,000$ at 5%

7 0

3 years ago

A bag contains only black marbles and white marbles . Ezra reached into the bag without looking , got 30 marbles , and found tha

Keith_Richards [23]

2/5

Since 12 out of 30 marbles were black, you can assume that the percentage of black marbles in the bag is 40% (Ex: 12/30=.4) The probability that the marble you pick is black is equal to the percentage of black marbles in the bag. 40% is equal to 2/5.

6 0

3 years ago

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PLZ HELP What is the mode interval for the histogram? Science Test Scores Frequency No Бел о об - 1 50-59 60-69 70-79 80-89 90-1

Ksju [112]

Answer: You are correct. The mode is between 90 and 100

This is because the tallest bar corresponds to this interval. The mode is the most frequent value.

4 0

3 years ago

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