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kotegsom [21]
3 years ago
14

What is the best way to study for the teas test

Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
8 0
Use your notes from that unit or previous years if you've done it before 
Blizzard [7]3 years ago
7 0
Use your notes, and study !
You might be interested in
Solving an Equation for a Given Variable
Reil [10]

Answer:

a=\frac {f-v}{t}

Step-by-step explanation:

f=v+at

It requires you to make a the subject of the formula

f-v=at

Dividing both sides by t then

a=\frac {f-v}{t}

Therefore, the equivalent for a is a=\frac {f-v}{t}

8 0
2 years ago
When deriving the quadratic formula by completing the square, what expression can be added to both sides of the equation to crea
nignag [31]

The expression that would be added to both sides is (b/2a)^2

<h3>How to determine the expression?</h3>

The equation is given as:

x^2 + b/ax + __ = c/a + __

Take the coefficient of x

b/a

Divide by 2

b/2a

Square the expression

(b/2a)^2

Hence, the expression that would be added to both sides is (b/2a)^2

Read more about quadratic equation at:

brainly.com/question/10449635

#SPJ1

6 0
1 year ago
2. Is 4x – 3 = 19 true, false, or open? <br> A)true<br> B)false<br> C)open
ElenaW [278]

Answer: B. False

Step-by-step explanation: Because you do

4x - 3 = 19

+3 +3 =4x = 22

You divide 4x divide by 4 and you get x

Then you divide 22 by 4 and get 5.5

So the answer is X = 5.5

6 0
3 years ago
To estimate μ, the mean salary of full professors at American colleges and universities, you obtain the salaries of a random sam
GenaCL600 [577]

Answer:

<h3>73220±566.72</h3>

Step-by-step explanation:

The formula for calculating the confidence interval is expressed as;

CI = xbar ± z*s/√n

xbar is the sample mean =  $73,220

z is the z score at 99% CI = 2.576

s is the standard deviation = $4400

n is the sample size = 400

Substitute the given values into the formula;

CI = 73,220 ± 2.576*4400/√400

CI = 73,220 ± 2.576*4400/20

CI = 73,220± (2.576*220)

CI = 73220±566.72

Hence a 99% confidence interval for μ is 73220±566.72

5 0
2 years ago
A researcher surveyed 220 residents of a city about the number of hours they
olga55 [171]

Answer:

Margin of error of 0.0485 hours.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

In this question:

\sigma = 0.35, n = 220

The margin of error is of:

M = z\frac{\sigma}{\sqrt{n}}

M = 1.96\frac{0.35}{\sqrt{200}}

M = 0.0485

Margin of error of 0.0485 hours.

5 0
2 years ago
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