4 years ago

A square is always which of these?

Mathematics

2 answers:

joja [24]4 years ago

7 0

Rectangle, hope this helps

yKpoI14uk [10]4 years ago

4 0

A square is a special kind of rectangle, having all the sides equal.

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Solve the inequalities by graphing. Identify the graph that shows the following equations.

Yuki888 [10]

Y>2x (0,0)—> (0+2, 0+1)
Y<3 Y=3 then shade downward
Horizontally

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3 years ago

The interior angles of a triangle measures 180?<br> True or false

Ymorist [56]

it is true because al triangles angles MUST add up to 180

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3 years ago

123.456 RONDED TO THE NEAREST HUNDREDTH.

anzhelika [568]

123.456 RONDED TO THE NEAREST HUNDREDTH.

Answer:

123.46

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3 years ago

Read 2 more answers

If h(x) = 5x -7,find the h(14)

Mrac [35]

B. That is the correct answer because h(14) = 63 when you divide it by 3

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4 years ago

Use the distance formula, show that the points (4,0), (2,1), and (-1,-5) form the vertices of a right triangle

mario62 [17]

Step-by-step explanation:

The distance formula between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the coordinates of the points.

$A(4,\ 0),\ B(2,\ 1),\ C(-1,\ -5)\\\\AB=\sqrt{(2-4)^2+(1-0)^2}=\sqrt{(-2)^2+1^2}=\sqrt{4+1}=\sqrt5\\\\AC=\sqrt{(-1-4)^2+(-5-0)^2}=\sqrt{(-5)^2+(-5)^2}=\sqrt{25+25}=\sqrt{50}\\\\BC=\sqrt{(-1-2)^2+(-5-1)^2}=\sqrt{(-3)^2+(-6)^2}=\sqrt{9+36}=\sqrt{45}$

If a ≤ b < c are the sides of the right triangle, then

a² + b² = c²

$\sqrt5$

used $(\sqrt{a})^2=a$ for a ≥ 0.

$AB^2+BC^2=AC^2$ therefore ΔABC is a right triangle.

6 0

3 years ago