Answer:
<h2><u><em>
x = 69°</em></u></h2><h2><u><em>
V = 103°</em></u></h2>
Step-by-step explanation:
the sum of the interior angles in a triangles is 180°, take away from 180 the know angles (34° and 77°) and you will have your answer
180 - 34 - 77 = 69°
Now we find angle V
The angle V and the angle of 77 ° are on a straight line, so the sum is 180°, from 180° you subtract 77 ° and you have the value of V
180 - 77 = 103 °
Try to relax. Your desperation has surely progressed to the point where
you're unable to think clearly, and to agonize over it any further would only
cause you more pain and frustration.
I've never seen this kind of problem before. But I arrived here in a calm state,
having just finished my dinner and spent a few minutes rubbing my dogs, and
I believe I've been able to crack the case.
Consider this: (2)^a negative power = (1/2)^the same power but positive.
So:
Whatever power (2) must be raised to, in order to reach some number 'N',
the same number 'N' can be reached by raising (1/2) to the same power
but negative.
What I just said in that paragraph was: log₂ of(N) = <em>- </em>log(base 1/2) of (N) .
I think that's the big breakthrough here.
The rest is just turning the crank.
Now let's look at the problem:
log₂(x-1) + log(base 1/2) (x-2) = log₂(x)
Subtract log₂(x) from each side:
log₂(x-1) - log₂(x) + log(base 1/2) (x-2) = 0
Subtract log(base 1/2) (x-2) from each side:
log₂(x-1) - log₂(x) = - log(base 1/2) (x-2) Notice the negative on the right.
The left side is the same as log₂[ (x-1)/x ]
==> The right side is the same as +log₂(x-2)
Now you have: log₂[ (x-1)/x ] = +log₂(x-2)
And that ugly [ log to the base of 1/2 ] is gone.
Take the antilog of each side:
(x-1)/x = x-2
Multiply each side by 'x' : x - 1 = x² - 2x
Subtract (x-1) from each side:
x² - 2x - (x-1) = 0
x² - 3x + 1 = 0
Using the quadratic equation, the solutions to that are
x = 2.618
and
x = 0.382 .
I think you have to say that <em>x=2.618</em> is the solution to the original
log problem, and 0.382 has to be discarded, because there's an
(x-2) in the original problem, and (0.382 - 2) is negative, and
there's no such thing as the log of a negative number.
There,now. Doesn't that feel better.
The question is incomplete:
1. A cosmetologist must double his/her salary before the employer con realize any profit from his/her work, Miss, Mead paid Miss, Adams $125,00 per week to start.
2. Miss. Mead pays Miss. Brown $125.00 per week. How much money must Miss. Brown take in for services if Miss. Mead is to realize $50.00 profit on her work? (Conditions on salary are the same as in problem 1)
ODS
a. $275.00 b. $325.00 c. $250.00 d. $300.00
Answer:
d. $300.00
Step-by-step explanation:
Given that a cosmetologist must double her salary before the employer can realize any profit from his/her work, for Miss. Mead to realize $50.00 profit on her work, you would have to determine the amount that doubles the salary of the cosmetologist and add the $50 needed as profit:
Salary= $125*2=$250
$250+$50= $300
According to this, the answer is that for Mead to realize $50.00 profit on her work, Miss. Brown must take $300.
444 ÷ 2 = 222
444 ÷ 3 = 148
90 ÷ 2 = 45
90 ÷ 3 = 30
90 ÷ 5 = 18
90 ÷ 10 = 9
45 ÷ 3 = 15
45 ÷ 5 = 9
So 444 can be divided into 2 and 3
90 can be divided into 2, 3, 5, and 10
45 can be divided into 3 and 5
Hope this helps. :)
