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3 years ago

Find the 5th term of the sequence which has a first of 1 and a common ratio of 2.3

Mathematics

1 answer:

sveticcg [70]3 years ago

3 0

Hello :

the nth term is : An =A1 × r^(n-1)

A1 = 1 r = 2.3 n = 5

A5 =1 × (2.3)^(5-1)=27.9841

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Sebastian wanted to order pizzas for $7 each. The delivery charge is $3.50. He has $20.

docker41 [41]

Answer:

he can buy 2

Step-by-step explanation:

8 0

2 years ago

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Round 10.95 to the nearest tenth

Serhud [2]

Hi there! To round 10.95 to the nearest tenth, we find the number in the tenth place, which is 9 and look one place to the right. Round up if the number is greater than 5 or equal to 5 and round down if its less than 5.

The answer is 11.0 or just 11.

Ed: Explanation below.

11.00

10.99

10.98

10.97

10.96

10.95 Look at the 9. Then look to the right. Do I round up or down?

10.94

10.93

10.92

10.91

10.90

If the number is greater or equal to 5, you round up. If the number is smaller than 5, you round down. 9 is greater than 5, so we round up.

Therefore, the answer is 11.

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2 years ago

A container has 12 and 3/4 cups of lemonade .asher gives each of his classmates 7/8 of a cup of lemonade . He gives away all of

Agata [3.3K]

Asher gave lemonade to 14 students

Solution:

Given that, A container has 12 and $\frac{3}{4}$ cups of lemonade

Asher gives each of his classmates $\frac{7}{8}$ of a cup of lemonade

To find: Number of classmates received the lemonade

From given question,

Total cups of lemonade = $12\frac{3}{4}$

$\rightarrow 12\frac{3}{4} = \frac{4 \times 12 + 3}{4} = \frac{51}{4}$

cups of lemonade received by each classmate = $\frac{7}{8}$

Thus, number of classmates received the lemonade can be found by dividing total cups of lemonade by cups of lemonade received by each classmate

$\rightarrow \frac{\frac{51}{4}}{\frac{7}{8}}=\frac{51}{4} \times \frac{8}{7}$

$\rightarrow 14.57$

Thus Asher gave lemonade to 14 students

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3 years ago

What does product rule of exponents say

LuckyWell [14K]

The rules of exponents are
$( x^{m})( x^{n})=( x^{m+n})$
$\frac{ x^{m} }{ x^{n} } = x^{m-n}$
$x^{ \frac{m}{n} } = \sqrt[n]{ x^{m} }$
$( x^{m} )( y^{m} )=(yx)^{m}$
$( x^{m})^{n}=x^{mn}$
$( \frac{x}{y})^{m}= \frac{x^{m}}{y^{m}}$
$x^{-n}= \frac{1}{x^{n}}$
these are just some basic ones

7 0

2 years ago

Read 2 more answers

WILL MARK BRAINLIEST

____ [38]

Answer:

512

Step-by-step explanation:

∛n = 8

n = 512

double check

∛512 = ∛(8)^3 = 8

3 0

3 years ago

Read 2 more answers