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2 years ago

Jade can choose 1 pair of pants and one shirt to wear today. Here are her choices.

Mathematics

1 answer:

djverab [1.8K]2 years ago

4 0

Answer:

the choices? nothing? i dont understand...

Step-by-step explanation:

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Hanna is driving 480 miles. She has already driven 312 miles. What percent of her trip has she completed?

SVEN [57.7K]

Answer:

68%

Step-by-step explanation:

Hope this helps! :)

I would appreciate brainliest, if not that's ok!

5 0

2 years ago

HELP ME, FEE BWAINLY

victus00 [196]

Answer:

2w-5 > (with an underline that means more than or equal to) 18

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

What is the distance between coordinates (-6.25,5) and (-3.75,2)

Oksi-84 [34.3K]

Answer:

$\sqrt{15.25}$

Step-by-step explanation:

To find the distance, we can use the distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ when the given points are $(x_1,y_1)$ and $(x_2,y_2)$

Plug in the points (-6.25,5) and (-3.75,2)

$d=\sqrt{(-6.25-x_1)^2+(5-y_1)^2}\\d=\sqrt{(-6.25-(-3.75))^2+(5-2)^2}\\d=\sqrt{(-6.25+3.75)^2+(5-2)^2}\\d=\sqrt{(-2.5)^2+(3)^2}\\d=\sqrt{6.25+9}\\d=\sqrt{15.25}$

Therefore, the distance between the two coordinates is $\sqrt{15.25}$ , or approximately 3.91.

I hope this helps!

6 0

2 years ago

Amir ran the first 200-meter leg of the relay race with a speed of 8,260 millimeters per second. Ryder ran the last 200-

kkurt [141]

Step-by-step explanation:

Convert the speeds of Amir and Ryder to meters per second (m/s).

Amir:

8260 mm/s = 8.260 m/s

Ryder:

930 cm/s = 9.30 m/s

9.30 m/s > 8.260 m/s, so:

Ryder ran approximately 1 meter per second faster than Amir.

3 0

2 years ago

Use the properties of limits to help decide whether the limit exists. If the limit exists, find its value. ModifyingBelow lim W

Sergeu [11.5K]

Answer:

The value of given limit problem is 0.

Step-by-step explanation:

The given limit problem is

$lim_{x\rightarrow \infty}\dfrac{6x^3+5x-7}{6x^4-4x^3-9}$

We need to find the value of given limit problem.

Divide the numerator and denominator by the leading term of the denominator, i.e., $x^4$

$lim_{x\rightarrow \infty}\dfrac{\frac{6x^3+5x-7}{x^4}}{\frac{6x^4-4x^3-9}{x^4}}$

$lim_{x\rightarrow \infty}\dfrac{\frac{6}{x}+\frac{5}{x^3}-\frac{7}{x^4}}{6-\frac{4}{x}-\frac{9}{x^4}}$

Apply limit.

$\dfrac{\frac{6}{ \infty}+\frac{5}{ \infty}-\frac{7}{ \infty}}{6-\frac{4}{ \infty}-\frac{9}{ \infty}}$

We know that $\frac{1}{\infty}=0$ .

$\dfrac{0+0-0}{6-0-0}$

$\dfrac{0}{6}$

$0$

Hence, the value of given limit is 0.

8 0

2 years ago