Answer:
A score of 150.25 is necessary to reach the 75th percentile.
Step-by-step explanation:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
A set of test scores is normally distributed with a mean of 130 and a standard deviation of 30.
This means that 
What score is necessary to reach the 75th percentile?
This is X when Z has a pvalue of 0.75, so X when Z = 0.675.




A score of 150.25 is necessary to reach the 75th percentile.
Answer:
whatever% of anything, is just (whatever/100) * anything.
there were a total of 560000 votes, now, off those some are valid and some are invalid.
we know 15% of that are invalid, that simply means that 85% are valid, since 85% + 15% is the whole thing, or 100%, if 15% are not good, the other 85% are the good ones.
how many are the valid ones anyway? well, 85% of 560000, which is just (85/100) * 560000.
we know that off those valid ones, the candidate got 75% of those, so how much is 75% of that?
well, (75/100) * [ (85/100) * 560000 ].
Step-by-step explanation:
Answer:
a) 45
Step-by-step explanation: