Answer:
Distance between A and B is 5400 meters
Step-by-step explanation:
Consider "D" the letter to identify distance between A and B
Let's use "t" to identify the time of the first encounter (Devi and Kumar), and create an equation that states that the distance covered by Devi (at 100 m/min) in time "t", is equal to the total distance D minus what Kumar has covered at his speed (80 m/min) in that same time:
Recall that distance equals the speed times the time:
distance= speed * time
First encounter:
100 * t = D - 80 * t
180 * t = D Equation (1)
Not, 6 minutes later (at time t+6) , Devi and Li Ting meet .
Then for this encounter the distance covered by Devi equals total distance d minus the distance covered by Li Ting:
100 *(t+6) = D - 75 * (t+6)
100 t + 600 = D - 75 t - 450
175 T + 150 = D Equation (2)
Now, let's equal equation (1) to equation (2), since D should be the same:
180 t = 175 t + 150
5 t = 150
t = 30
Then the time t (first encounter) is 30 minutes. Knowing this, we can use either equation to find D:
From Equation (1) for example: D = 180 * t = 180 * 30 = 5400 meters
Answer:
Carla needs to make at least 11 two-pointer shots in the surrent game
Step-by-step explanation:
The first thing we can do is to find the difference between the number of points that Carla scored in her first game and her second game.
This will be 46 - 24 = 22 points difference
Carla needs to make a certain number of two-pointers to get at least the same score she had in her previous game.
We can get this number of two-pointers that needed to be made by dividing the difference in scores by 2
i.e number of two-pointer shots = 22/2 =11 shots
Therefore, Carla needs to make at least 11 two-pointer shots to be able to get the same score in her current game.
Answer:
162-x=180
x=342
Step-by-step explanation:
Answer:
173
Step-by-step explanation:
To solve a quadratic equation like 
, you can use the quadratic formula
In your case, 
, so the formula becomes
We can simplify the expression:
Since -3 is negative, its square root is computed as
So, the solutions are
